(a)
The plane is closer to which airport.
The plane is closer to our airport.
Given:
The plane is on a hyperbolic path and according to pilot instrument panel, our airport’s signal comes
Calculation:
As, the signal of our airport reaches faster than another hence, it is clear that airplane is closer to our airport.
Conclusion:
The plane is closer to our airport.
(b)
The differences in distance from the plane to the two airports.
The difference in distance is
Given:
Signal travels at the rate of
Calculation:
As, the difference between arriving of signal from the airport is
Conclusion:
The difference in distance is
(c)
The equation of the flight path.
The equation is
Given:
The plane is on a hyperbolic path and according to pilot instrument panel, our airport’s signal comes
Calculation:
The difference in distance is
Now, the distance between the airport is
---------------------------------
Where:
Hence,
As, the flight follows the hyperbola path. Hence, the equation becomes:
Conclusion:
The equation is
(d)
The graph hyperbola.
The graph is drawn.
Given:
The plane is on a hyperbolic path and according to pilot instrument panel, our airport’s signal comes
Calculation:
The hyperbolic equation is:
Now, the graph is:
Conclusion:
The graph is drawn.
Chapter 10 Solutions
High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11
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