Concept explainers
a)
Interpretation:
The IUPAC name of the
Concept introduction:
The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.
To give:
The IUPAC name of the alkyl halide shown.
Answer to Problem 14VC
The alkyl halide given is
Its IUPAC name is cis- 1- chloro-3-methylcyclohexane.
Explanation of Solution
The compound has a cyclohexane ring with a Cl atom on C1 and a methyl on C3 both at equatorial positions. Hence its name is cis- 1- chloro-3-methylcyclohexane.
The IUPAC name of the alkyl halide shown is cis- 1- chloro-3-methylcyclohexane.
b)
Interpretation:
The IUPAC name of the alkyl halide is to be given.
Concept introduction:
The longest continuous carbon chain in the molecule is chosen. The chain is numbered from the end which gives lowest number to the substituent either halo or alkyl group present. If different halogens are present they are numbered and listed in the alphabetical order while writing the name. If same two alternatives exist for different substituents, then the chain is numbered from the end that gives lowest number to the substituent that has alphabetical preference.
To give:
The IUPAC name of the alkyl halide shown.
Answer to Problem 14VC
The alkyl halide given is
Its IUPAC name is 4-chloro-2-methyl-2-heptene.
Explanation of Solution
The compound has a seven carbon straight chain with a double bond between C2 & C3, a Cl atom on C4 and a methyl on C3. Hence its name is 4-chloro-2-methyl-2-heptene.
The IUPAC name of the alkyl halide shown is 4-chloro-2-methyl-2-heptene.
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Chapter 10 Solutions
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