Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 2 Terms (12 Months) Printed Access Card
9th Edition
ISBN: 9781337583817
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 11, Problem 11.11P
To determine
Calculate the primary consolidation settlement of the clay layer.
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For the soil profile shown below, estimate the consolidation settlement occur in the clay layer if:
1- Clay is normally consolidated.
2- The oc= 140 kN/m².
175 kN/m?
1.0 m
Sand y=17.5 kN/m³
CR
1.0 m
Sand ysat = 22 kN/m³
Ysat = 22 kN/m
WS
1.0 m
3.0 m
Clay, Ysat = 20 kN/m³, e= 0.55,
Cc= 0.25, C,= 0.05
1.5 m
Silty sand ysat = 19 kN/m³
The compression curve (void ratio, e
for a certain
vs. effective stress,
clayey soil is a straight line in a
semi-logarithmic plot and it passes
(e = 1.2; = 50kPa)
through the points (e = 1.2; 0)
V
and (e=0.6;=800kPa). The
compression index (up to two decimal
places) of the soil is
3. For a normally consolidated clay, the
following were recorded; confining
pressure= 03 = 140KPa and Aod=264
KPa. Find Ø.
Chapter 11 Solutions
Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 2 Terms (12 Months) Printed Access Card
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- 5 The compression curve (void ratio, e vs. effective stress, o) for a certain clayey soil is a straight line in a semi-logarithmic plot and it passes through the points (e = 1.2; o = 50 kPa) and (e=0.6; o = 800 kPa). The compression index (up to two decimal places) of the soil is 100arrow_forwardThe results of a consolidated undrained test, in which o3 = 392 kN/m?, on a normally consolidated clay are given as: Axial strain (%) Ao(kN/m²) ug(kN/m²) 0.5 0.75 156 196 226 235 250 245 240 235 99 120 132 147 161 170 173 175 1.3 2 3 4 4.5 Draw the K; line in a P' versus q' diagram. Also draw the s tress path for this test in the diagram.arrow_forward4. In a consolidated-drained triaxial test on a clay that is normally consolidated, the results are as follows: O3 = 15 lb/in 2 (Aoa)f = 11 lb/in? (Aua)f = 7.2 lb/in? a) Determine the consolidated-undrained friction angle. %3D b) Calculate the drained friction angle.arrow_forward
- Problem l: For Problem Number 30. A layered soil has the following data; H= 1.5 m k,= 10°cm/sec k2= 3.0 x 10°cm/sec H2= 2.5 m H3= 3.0 m k3= 3.5 x 10°cm/sec 30) Determine the ratio kH(eq)/K vleg). a) 36.80 b) 37.27 c) 35.40 d) 33.90arrow_forwardA soil profile shown is subjected to a load of 48 kN/m2 at the ground surface. The preconsolidation pressure of the clay Pc = 160 kPa. Determine the settlement of the clay layer caused by primary consolidation. Use Cs = 1/5 Cc. 48 kN/m2 ground surface 4m Sand Ys =16 kN/m³ ground water țablę 6m Y sat =18 kN/m³ Clay 3m 6m Ysat =19 kN/m³ Ans. 71 mmarrow_forwardThe compression curve (void ratio, e vs. effective stress, o) for a certain clayey soil is a straight line in a semi-logarithmic plot and it passes through the points (e = 1.2; o = 50 kPa) and (e = 0.6; o = 800 kPa). The compression index (up to two decimal places) of the soil isarrow_forward
- Q.3. Calculate the total primary consolidation settlement of the soil layres as showr Figure Q3 below. ( 607 )kN EGL Sand Y = 18 kN/m 2m 2 m x 3 m 1 m Assume, Ysat = 18.5 kN/m³ C. = (1/6) Cc for both layers Clay layer-1 eo = 0.92 2 m Cc = 0.154 OCR=1 Silty Sand layer, Ysat = 19 kN/m³ Ysat = 19.5 kN/m³ eo = 0.564 Cc = 0.104 Clay layer-2 3 m OCR=1.6 Pervious Rock layer Figure Q3: Soil Layers Earrow_forwardThe following data are given for normally consolidated clay: Thickness=2.6m Primary Cc=0.3 Secondary Cc=0.02 e=0.8 Average Pressure=127 kPa Change in pressure (vertical) =46 kPa Determine the following 1. Primary Consolidation Settlement (Ans. 58.17mm) 2. Secondary Settlement five years after the completion of the primary settlement. The time for completion of primary settlement is 1.5 years. (Ans. 15.4mm)arrow_forwardFor a normally consolidated insensitive clay ∅_CD = 30°. Deviator stress at failure of the same soil is 250 kN/m2 in CU test. If Skempton’s A-parameter at failure is 0.62, find out the confining pressure during the consolidation state. a. 260 b. 270 c. 280 d. 250arrow_forward
- -) A clay stratum has 2.5 m thickness and has initial overburden pressure of 45 kN/m². The clay is over consolidated with a preconsolidation pressure of 65 kN/m². Find the final settlement due to increment of pressure of 55 kN/m² at the middle of clay layer. Use the following data: Initial void ratio = 1.2 Compression index = 0.27 Swelling index = 0.06arrow_forwardFor a normally consolidated insensitive clay ∅_CD = 30°. Deviator stress at failure of the same soil is 250 kN/m2 in CU test. If Skempton’s A-parameter at failure is 0.62, find out the confining pressure during the consolidation state. Show free body diagram a.260 b.250 c.270 d.280arrow_forwardWhat is the equivalent coefficient of permeability (k) for all soil layers? where equivalent k(2 and 3) = 4.58 k1 and k4 = 4.23 k1 10 8 IB D K2 N K3 N K1 K4 .a k1 2.738 .b k1 44.050 .C k1 3.568 .d k1 2.382 28arrow_forward
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