EBK BASIC BIOMECHANICS
7th Edition
ISBN: 9780100409453
Author: Hall
Publisher: YUZU
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Chapter 11, Problem 4IP
A kicker’s extended leg is swung for 0.4 s in a counterclockwise direction while accelerating at 200 deg/s2. What is the angular velocity of the leg at the instant of contact with the ball? (Answer: 80 deg/s, 1.4 rad/s)
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Chapter 11 Solutions
EBK BASIC BIOMECHANICS
Ch. 11 - The relative angle at the knee changes from 0 to...Ch. 11 - Identify the angular displacement, the angular...Ch. 11 - How many revolutions are completed by a top...Ch. 11 - A kickers extended leg is swung for 0.4 s in a...Ch. 11 - The angular velocity of a runners thigh changes...Ch. 11 - A tennis racquet swung with an angular velocity of...Ch. 11 - A 1.2-m golf club is swung in a planar motion by a...Ch. 11 - David is fighting Goliath. If Davids 0.75-m sling...Ch. 11 - A baseball is struck by a bat 46 cm from the axis...Ch. 11 - A polo players arm and stick form a 2.5-m rigid...
Ch. 11 - Explain how the velocity of the ball in Problem 4...Ch. 11 - A majorette in the Rose Bowl Parade tosses a baton...Ch. 11 - A cyclist enters a curve of 30-m radius at a speed...Ch. 11 - A hammer is being accelerated at 15 rad/s2. Given...Ch. 11 - A speed skater increases her speed from 10 m/s to...
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- The “mean-speed theorem” for finding average velocity under constant acceleration, proposed by the Oxford Calculators, and demonstrated geometrically by Nicole Oresme, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forwardThe “mean-speed theorem” for calculating average velocity under constant acceleration, developed by Thomas Bradwardine and the Mertonian Calculators at Oxford University, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) C. (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forwardAn airplane flying directly eastward at a constant speed travels 293 km in 2.0 h. (a) what is the average velocity of the plane? (b) what is the instantaneous velocity?arrow_forward
- a toy car rolls 10 meters (m) across the floor. it takes 5 seconds (s) to cross this distance. what is the speed of this car?arrow_forwardA scientist was investigating if differences in the frictional work performed on a model car can change depending on its mass (in grams) and whether the car moves up or down an inclined plane. They decided to measure the amount of frictional force experienced by the model car and the distance it traveled in meters. The scientists were able to evaluate the frictional work using the following data. Mass (g) Distance (m) Force Work Done by Friction (J) car going up the incline 100 39 0.063 2.457 car going down the incline 70 39 0.2309 ? It is known that the relationship between force and distance determines the work done by friction (W+). W₁ = fd Wf work done by friction f = force d = distance Question: How much work done by friction was exerted on the car as it moved down the inclined plane? You may use a calculator. 1 2.457 9.005 11.46 16.16 PREVIOUS FINISHarrow_forwardThese figures show that: S Vor (1-min¹) 30 A 2.5 20 1.5 1.0 0.5 (50) 10 Concentric Eccentric Exercise rate (100) 20 (150) Integrated EMG (counts min) B 600 400 200 (50) 30 10 Mean torque on pedals (Nm) (100) Concentric 20 Exercise rate (200) (150) Eccentric 30 O concentric contractions require more oxygen and more EMG than eccentric contractions O concentric contractions are easier to perform than eccentric contractions O eccentric contractions place a greater demand on the cardiovascular and nervous systems compared to concentric contractions O eccentric contractions use less oxygen but more EMG than concentric contractionsarrow_forward
- You have measured the following data for enzyme X. Substrate Vo concentration (micromolar (mM) Isec) 0.05 10 0.1 60 0.5 175 1 250 350 490 10 492 20 494 50 499 100 498 200 498arrow_forwardCalculate the total amount of work performed in 5 minutes of exercise on the cycle ergometer, given the following:Resistance on the flywheel = 25 NCranking speed = 60 rpmDistance traveled per revolution = 6 metersarrow_forward72. Find J and K in the rotational system shown in Figure P4.18 to yield a 30% overshoot and a sett- ling time of 3 seconds for a step input in torque. [(Section: 4.6] 000 K FIGURE P4.18arrow_forward
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