21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 11, Problem 4QP
To determine
The reason for the moon Io to have the most volcanic activity in the solar system.
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Chapter 11 Solutions
21st Century Astronomy
Ch. 11.1 - Prob. 11.1CYUCh. 11.2 - Prob. 11.2ACYUCh. 11.2 - Prob. 11.2BCYUCh. 11.3 - Prob. 11.3CYUCh. 11.4 - Prob. 11.4CYUCh. 11 - Prob. 1QPCh. 11 - Prob. 2QPCh. 11 - Prob. 3QPCh. 11 - Prob. 4QPCh. 11 - Prob. 5QP
Ch. 11 - Prob. 6QPCh. 11 - Prob. 7QPCh. 11 - Prob. 8QPCh. 11 - Prob. 9QPCh. 11 - Prob. 10QPCh. 11 - Prob. 11QPCh. 11 - Prob. 12QPCh. 11 - Prob. 13QPCh. 11 - Prob. 14QPCh. 11 - Prob. 15QPCh. 11 - Prob. 16QPCh. 11 - Prob. 17QPCh. 11 - Prob. 18QPCh. 11 - Prob. 19QPCh. 11 - Prob. 20QPCh. 11 - Prob. 21QPCh. 11 - Prob. 22QPCh. 11 - Prob. 23QPCh. 11 - Prob. 24QPCh. 11 - Prob. 25QPCh. 11 - Prob. 26QPCh. 11 - Prob. 27QPCh. 11 - Prob. 28QPCh. 11 - Prob. 29QPCh. 11 - Prob. 31QPCh. 11 - Prob. 32QPCh. 11 - Prob. 33QPCh. 11 - Prob. 34QPCh. 11 - Prob. 35QPCh. 11 - Prob. 36QPCh. 11 - Prob. 37QPCh. 11 - Prob. 38QPCh. 11 - Prob. 40QPCh. 11 - Prob. 41QPCh. 11 - Prob. 42QPCh. 11 - Prob. 43QPCh. 11 - Prob. 44QPCh. 11 - Prob. 45QP
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- Explain why the amount of geological activity on Jupiter’s moons varies with distance from the planet.arrow_forwardWhy would you include the Moon in a comparison of the Terrestrial planets?arrow_forwardWhat evidence is there that Neptune’s moon Triton has been geologically active recently?arrow_forward
- Some astronomers argue that Jupiter and Saturn are unusual, while other astronomers argue that all planetary systems should contain one or two such giant planets. What do you think? Support your argument with evidence.arrow_forwardWhy do astronomers conclude that the crust on Mars must be thicker than Eths crust?arrow_forwardYou are a planetary scientist studying the atmosphere of Jupiter through a large telescope when you observe an asteroid approaching the planet. This asteroid is large, so you know it is held together by gravity rather than the cohesive forces that hold a large rock together. If the asteroid gets too close to Jupiter, the massive tidal forces will tear it apart, scattering small particles that will add to the ring system. You have calculated the closest distance the asteroid will come to Jupiter. How do you know if the asteroid will survive? a. A measure of the cohesive gravitational force holding such an asteroid together is the gravitational field on the surface due to the mass of the asteroid. This field is independent of the distance of the asteroid from Jupiter. Calculate the gravitational field at the surface of the asteroid due only to the mass of the asteroid. Assume the asteroid has a diameter of 10,000 km and a density of 1300 kg/m3. b. Tidal forces from Jupiter tend to disrupt the asteroid by pulling it apart. The tidal forces depend on the distance between Jupiter and the asteroid. There is a distance between Jupiter and the asteroid known as the Roche limit where the tidal forces are balanced by the asteroids own cohesive gravitational force. If the asteroid is within the Roche limit, it will be torn apart. Figure P7.60 shows Jupiters gravitational field as a function of distance from its center. By looking at this graph, can you determine an approximate value for the Roche limit for this asteroid in the vicinity of this planet? c. What will happen to the Roche limit if we consider an asteroid of lower density? FIGURE P7.60arrow_forward
- Why doesn't Mars have active volcanoes today? A) all of the lava already escaped B) the planet lost its internal heat to cold space C) the volcanoes are just dormant and will erupt againarrow_forward1) Contrast the difference between Comets and Asteroids – describe the orbit, composition, and how they appear in the sky. 2)Explain how the terrestrial planets and the Jovian planets ended up so different.arrow_forwardJupiter's moon, Io, loses about 1190.0 kg/s of sulfur dioxide to Jupiter's magnetosphere. At this rate, what percent of its mass would Io lose in 3.0 × 109 years? Io has a mass of about 1 × 1023 kg and there are 3.15 × 107 seconds in a a year.arrow_forward
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