Chapter 1.1, Problem 95E

To determine

To Write: the linear equation that gives dollar value of product in terms of year.

Answer to Problem 95E

  $V=56,400-2000t$

Explanation of Solution

Given:

Product value in $2018$ is $ $20,400$ and decrease rate is $ $2000$ per year.

Calculation:

Let $V_{2018}$ represent product value.

Let $t$ represent time in years. In the year $2018$ ,time is $t=18$ .

Since, product value in year $2018$ is given therefore find product value in year $2000$ .

In $2000$ , $t=0$ .

In year $2018$ , Equation for product value is.

  $V_{2018}=V_{2010}+Rt$

Substituting $V_{2018}=\$20,400$ , $R=-2000$ and $t=18$ .

  $\begin{array}{l}20,400=V_{2000}-2000\times 18\\ V_{2000}=20400+36000\\ V_{2000}=56,400\end{array}$

Linear equation in terms of $t$ is.

  $\begin{array}{l}V=V_{2000}+Rt\\ V=56,400-2000t\end{array}$

Therefore, the answer is $V=56,400-2000t$ .