Chapter 11.1, Problem 50PPS

To determine

To Find: Theforce needed to move an object $15$ feet is the same amount of work is done.

Answer to Problem 50PPS

  $60N$

Explanation of Solution

Given: The amount of force required to do certain amount of work in moving a object is inversely proportional to the distance that the object is moved. Suppose $90N$ of force is required to move an object $10$ feet.

Let $x$ be the distance movedand $y$ be force.

Then

The table representing the situation is

  

Product rule for Inverse variation

  $x_1{y}_1=x_2{y}_2$

Here

  $\begin{array}{l}{x}_1=10\\ y_1=90\\ x_2=15\\ y_2=?\end{array}$

Then

  $\begin{array}{l}{x}_1{y}_1=x_2{y}_2\\ (10)(90)=(15)(y_2)\\ 900=15y_2\\ y_2=\frac{900}{15}\\ y_2=60\end{array}$

Hence

Theforce needed to move an object $15$ feet is the same amount of work is done is $60N$ .