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Use the function in Problem 9 to find the indicated probabilities.
(A)
(B)
(C)
9.
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Chapter 11 Solutions
Pearson eText for Calculus for Business, Economics, Life Sciences, and Social Sciences -- Instant Access (Pearson+)
- To illustrate the proof of Theorem 1, consider the ran-dom variable X, which takes on the values −2, −1, 0, 1, 2, and 3 with probabilities f(−2), f(−1), f(0), f(1), f(2),and f(3). If g(X) = X2, find(a) g1, g2, g3, and g4, the four possible values of g(x);(b) the probabilities P[g(X) = gi] for i = 1, 2, 3, 4;(c) E[g(X)] = 4i=1gi ·P[g(X) = gi], and show that it equals xg(x)·f(x)arrow_forward1. Determine the requested probabilities. -2 -1 1 2 f(x) 0.2 0.4 0.1 0.2 0.1 a) P(xs 2) b) P(x > -2) c) P(-1 sx< 1) d) P(x = 2 or xs-1)arrow_forward38. If f(x) and g(x) = x2-4, then what is f(g( -2))? %3! x+ 4arrow_forward
- Suppose 10% of the population of WVU students has tested positive for COVID-19, W1 represents the part of the population that has tested positive and W2 represents those who tested negative. X denotes a test result that the person has tested positive for COVID-19. P(W1) = 0.10 individual tested positiveP(W2) = 0.90 Individual tested negativeP(X|W1) = 0.80 test shows the individual tested positive and is correctP(X|W2) = 0.30 test incorrectly shows the individual is positiveRandomly select an individual and preform the test. The result shows the person tested positive, what is the probability that the test is correct? Use Bayes' theorem to solve.arrow_forwardIf ƒ = {(1, − 1), ( − 3, ¹), the following values of f and g. a. f(1) b. g(2) = c. g = 3 9 (²1) 4 d. f(2) e. g( − 3) = = f. f(T) = (2, , (2, 1), (5, 1)} = and g = Preview = {(2, -1), − 1), ( – 3, − 2), (³, − ¹)}, 1 find each ofarrow_forward3. Given p(x) = (1+ 2x)*.arrow_forward
- 1.Suppose that one word is to be selected at random from the sentence "THE GIRL PUT ON HER BEAUTIFUL RED HAT". If X denotes the number of letters in the word that is selected, (1) What is the value of E(X)? (2) What is the value of Var(X)?arrow_forward2. f(x)=-5* +3arrow_forwardSuppose that the functions s and t are defined for all real numbers x as follows. s (x)%3x-5 t (x) =3x+3 Write the expressions for (s-t)(x) and (s t)(x) and evaluate (s+t)(4). (+-)(+) = [0 %3D (s-t)(x) = [ %3D (s+t)(4) = [ %Darrow_forward
- Pr[A]=7/9 Pr[B]=2/9 Pr[a|A]=3/5 Pr[b|A]=2/5 Pr[a|B]=1/3 Pr[b|B]=2/3 Find the following missing probabilities: (1) Pr[B]= (2) Pr[b]= (3) Pr[b|B]= (4) Pr[B|b]=arrow_forwardConsider the following function for a value of k.f(x) ={3kx/7, 0 ≤ x ≤ 1 3k(5 − x)/7 , 1 ≤ x ≤ 30, otherwise.Comment on the output of these probabilities below, what will be theconclusion of your output.(i)Evaluate k.(ii)find (a) p(1 ≤ x ≤ 2) (b) p(x > 2). (u) p(x ≤ 8/3).arrow_forward4. Use Lagrang interpolation method to find f(1) based on the following data: -3 2 -1 3 ソ=fx)| 1 2 4 8.arrow_forward
- Calculus For The Life SciencesCalculusISBN:9780321964038Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.Publisher:Pearson Addison Wesley,
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