Chapter 11.2, Problem 43CCR

To determine

To find: Estimate each square root to nearest integer.

Answer to Problem 43CCR

Closest integer to $\sqrt{38}$ is $6$

Explanation of Solution

Given information:

  $\sqrt{38}$

  $\sqrt{38}$

The first perfect square less than $38$ is $36$ that is $\sqrt{36}=6$

The first perfect square greater than $38$ is $49$ that is $\sqrt{49}=7$

So, the square root of $38$ is between the integers $6$ and $7$

Since $38$ is closer to $36$ than to $49$ .

So, $\sqrt{38}$ is closer to $6$ than to $7$

Therefore,

Closest integer to $\sqrt{38}$ is $6$