Chapter 11.6, Problem 25PPS

To determine

To Find: The area of the given figure.

Answer to Problem 25PPS

  $A=81\text{ sq}\text{. mm}$

Explanation of Solution

Given information:

The given figure is

Concept and Formula Used:

Area of rectangle $A=\text{length}\times \text{width}$ & Area of trapezoid $A=\frac{1}{2}h\left(a+b\right)$

Calculation:

The given figure is combination of rectangle and trapezoid.

To find the area of the figure add the area of rectangle and trapezoid.

The sides of the rectangle is $l=9.9mm\&w=6mm$ and the bases of trapezoid is equal to $a=9.9mm\&b=4.5mm$ and height of trapezoid is $h=9-6=3mm$

Area of figure is sum of area of rectangle and trapezoid.

  $\begin{array}{l}\text{Area}=\text{Area of rectangle}+\text{Area of trapezoid}\\ A=\text{length}\times \text{width}+\frac{1}{2}h\left(a+b\right)\\ \text{where }l=9.9mm,w=6mm,a=9.9mm,b=4.5mm\&h=3mm\\ A=9.9\times 6+\frac{1}{2}\left(3\right)\left(9.9+4.5\right)\\ A=59.4+\frac{1}{2}\left(3\right)\left(14.4\right)\\ A=59.4+21.6\\ A=81\text{ sq}\text{. mm}\end{array}$

Conclusion:

  $A=81\text{ sq}\text{. mm}$