Give the Arrhenius equation. Take the natural log of both sides and place this equation in the form of a straight-line equation ( y = mx + b ) . What data would you need and how would you graph those data to get a linear relationship using the Arrhenius equation? What does the slope of the straight line equal? What does the y -intercept equal? What are the units of R in the Arrhenius equation? Explain how if you know the rate constant value at two different temperatures, you can determine the activation energy for the reaction.
Give the Arrhenius equation. Take the natural log of both sides and place this equation in the form of a straight-line equation ( y = mx + b ) . What data would you need and how would you graph those data to get a linear relationship using the Arrhenius equation? What does the slope of the straight line equal? What does the y -intercept equal? What are the units of R in the Arrhenius equation? Explain how if you know the rate constant value at two different temperatures, you can determine the activation energy for the reaction.
Solution Summary: The author explains the mathematical expression of the Arrhenius equation, the data required when the natural log is taken on both sides and the equation is placed in a straight-line equation.
Give the Arrhenius equation. Take the natural log of both sides and place this equation in the form of a straight-line equation (y = mx + b). What data would you need and how would you graph those data to get a linear relationship using the Arrhenius equation? What does the slope of the straight line equal? What does the y-intercept equal? What are the units of R in the Arrhenius equation? Explain how if you know the rate constant value at two different temperatures, you can determine the activation energy for the reaction.
In a chemical reaction, X reacts to produce Y:
3X → 2Y
The concentrations of X and Y are measured with time:
t/s: 0.00 1.00 2.00 4.00 8.00 16.0
X/M: 1.000 0.705 0.526 0.352 0.264 0.250
Y/M: 0.000 0.197 0.316 0.432 0.491 0.500
The concentration of reactant X varies with time:
X = (X0 – XF) e–kt + XF
The concentration of product Y varies with time:
Y = (YF – Y0) (1 – e–kt)
What is the rate constant k for the reaction?
Question 18 options:
k = 0.33
k = 0.25
k = 0.50
What is amount of Y produced after 3.00 s?
Question 19 options:
0.375 M
0.388 M
0.362 M
At what time does the concentration of X become 0.5 M?
Question 20 options:
2.1 s
2.2 s
2.3 s
* Question Completion Status:
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An untreated sugar cube does not burn very well when held over a lighted match. A sugar cube coated with cigarette ash readily ignites and burns. All of the cigarette ash
remains unchanged after the reaction, but the sugar is burned completely. Manufacturers of cigarettes add chemicals that support burnung into the cigarettes. The factor that
caused this change in rate is the
☐ a. presence of a catalyst in the ash
, increase in surface area
○ b.i
c. nature of reactants
d. increase in concentration
14K
Classify each chemical reaction:
Reaction
FeCl₂(aq) + Na₂S (aq)
2Li (s) + 2HCl(aqg) → 2LiCl (aq) + H₂ (g)
FeCl₂ (aq) + Bas (aq) →
BaCl₂ (aq) + FeS (s)
2Na Cl (aq) + Fes (s)
Туре
✓ choose one
combination
decomposition
single displacement
metathesis
none of the above
V
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