Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393600681
Author: Gilbert
Publisher: W. W. Norton & Company
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Chapter 12, Problem 12.20QA
Interpretation Introduction
To explain:
Whether the carbohydrates experience an increase or decrease in entropy when they are digested and decomposed into simple sugars.
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Chapter 12 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 12 - Prob. 12.1VPCh. 12 - Prob. 12.2VPCh. 12 - Prob. 12.4VPCh. 12 - Prob. 12.5VPCh. 12 - Prob. 12.6VPCh. 12 - Prob. 12.8VPCh. 12 - Prob. 12.9VPCh. 12 - Prob. 12.10VPCh. 12 - Prob. 12.11QACh. 12 - Prob. 12.12QA
Ch. 12 - Prob. 12.13QACh. 12 - Prob. 12.14QACh. 12 - Prob. 12.15QACh. 12 - Prob. 12.16QACh. 12 - Prob. 12.17QACh. 12 - Prob. 12.18QACh. 12 - Prob. 12.19QACh. 12 - Prob. 12.20QACh. 12 - Prob. 12.21QACh. 12 - Prob. 12.22QACh. 12 - Prob. 12.23QACh. 12 - Prob. 12.24QACh. 12 - Prob. 12.25QACh. 12 - Prob. 12.26QACh. 12 - Prob. 12.27QACh. 12 - Prob. 12.28QACh. 12 - Prob. 12.29QACh. 12 - Prob. 12.30QACh. 12 - Prob. 12.31QACh. 12 - Prob. 12.32QACh. 12 - Prob. 12.33QACh. 12 - Prob. 12.34QACh. 12 - Prob. 12.35QACh. 12 - Prob. 12.36QACh. 12 - Prob. 12.37QACh. 12 - Prob. 12.38QACh. 12 - Prob. 12.39QACh. 12 - Prob. 12.40QACh. 12 - Prob. 12.41QACh. 12 - Prob. 12.42QACh. 12 - Prob. 12.43QACh. 12 - Prob. 12.44QACh. 12 - Prob. 12.45QACh. 12 - Prob. 12.46QACh. 12 - Prob. 12.47QACh. 12 - Prob. 12.48QACh. 12 - Prob. 12.49QACh. 12 - Prob. 12.50QACh. 12 - Prob. 12.51QACh. 12 - Prob. 12.52QACh. 12 - Prob. 12.53QACh. 12 - Prob. 12.54QACh. 12 - Prob. 12.55QACh. 12 - Prob. 12.56QACh. 12 - Prob. 12.57QACh. 12 - Prob. 12.58QACh. 12 - Prob. 12.59QACh. 12 - Prob. 12.60QACh. 12 - Prob. 12.61QACh. 12 - Prob. 12.62QACh. 12 - Prob. 12.63QACh. 12 - Prob. 12.64QACh. 12 - Prob. 12.65QACh. 12 - Prob. 12.66QACh. 12 - Prob. 12.67QACh. 12 - Prob. 12.68QACh. 12 - Prob. 12.69QACh. 12 - Prob. 12.70QACh. 12 - Prob. 12.71QACh. 12 - Prob. 12.72QACh. 12 - Prob. 12.73QACh. 12 - Prob. 12.74QACh. 12 - Prob. 12.75QACh. 12 - Prob. 12.76QACh. 12 - Prob. 12.77QACh. 12 - Prob. 12.78QACh. 12 - Prob. 12.79QACh. 12 - Prob. 12.80QACh. 12 - Prob. 12.81QACh. 12 - Prob. 12.82QACh. 12 - Prob. 12.83QACh. 12 - Prob. 12.84QACh. 12 - Prob. 12.85QACh. 12 - Prob. 12.86QA
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- a 75 kg adult requires a calorie intake of 2000 Cal of food every 24 hours. The food is metabolized, and the free energy is used to synthesis ATP for useful work. {each Calorie listed on food labels corresponds to 1.0 Cal in biochemical terms}. Assuming that the efficiency of converting food energy into ATP is 50%. Calculate the weight of ATP used by this human in 24 hours and the percentage of the person’s body weight that this represents. {the formula mass of ATP is 505 g/mol and each mole of ATP is equivalence to 7.30 Cal}arrow_forwardActual free-energy change is a function of the reactant and product concentrations and the temperature at which the reaction occurs. AG = Go + RT In Use the equation for the actual free-energy change to plot AG against In Q at 25 °C for the five concentrations of ATP, ADP, and P₁ shown in the table. The AG' for the reaction is -30.5 kJ/mol. Concentration (mm) 0.2 5.0 14.9 O O AG (kJ/mol) Metabolite ATP ADP P₁ Select the graph that plots the data. AG (kJ/mol) 0 -20 -40 -~ 0 200 0 -200 [C]c[D]d [A]a[B]b -400 T 2 5 0.2 10 2 T 4 3 2.2 12.1 InQ 6 4 InQ 6 8 1 4.2 14.1 10 8 5 25 10 AG (kJ/mol) AG (kJ/mol) 0 -20 -40 -10 -8 0 -20 -40 -6 -4 InQ -2 0arrow_forwardP4(s) + 5O2(g) → P4O10(s) ∆ G° = -2697.0 kJ/mol2H2(g) + O2(g) → 2h2O(g) ∆ G° = - 457.18 kJ/mol 6H2O(g) + P4O10(s) → 4H3PO4(1) ∆G° = - 428.66 kJ/mol What is the standard free energy of formation, ∆ Gf degree, for phosphoric acid? a: 11243.3 kj/mol b: -11243.3 kj/mol c: 4497.2 kj/mol d: -4497.2 kj/molarrow_forward
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