STRUCTURAL ANALYSIS (LL)
6th Edition
ISBN: 9780357030967
Author: KASSIMALI
Publisher: CENGAGE L
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Question
Chapter 12, Problem 14P
To determine
Find the approximate axial forces, shears, and moments for the all members of the frames using cantilever method.
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Chapter 12 Solutions
STRUCTURAL ANALYSIS (LL)
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- 2. The vertical force P of magnitude 150 Ib is applied to the frame shown in Fig. (a). Resolve P into components that are parallel to the members AB and AC of the truss. 73° B P 28° (a)arrow_forwardDetermine the reactions and draw the shear and bending moment diagrams for the beams shown by using the slope deflection method. PLEASE REFER TO FIG. P16.3arrow_forwardDetermine forces and moment in each member of the frame by performing Portal Method. E 80 kN 8 m A 8 m 5 m FIG. P12.8, P12.16arrow_forward
- 1-39. Replace the single force in Fig. P 1-39 by a force which acts along line CD and a couple. 2,000 30 FIG. P 1-39arrow_forwardDetermine the approximate axial forces, shears, and moments for all the members of the frames shown in Figs. P12.6 through P12.13 by using the portal method. H -67.5 kN 3.6 m to -D - 112.5 kN E F 3.6 m B E 6m +4.5 m FIG. P12.11, P12.19arrow_forwardEXAMPLE 3.3 Determine the force in each member of the scissors truss shown in Fig. 3-2la. State whether the members are in tension or compression. The reactions at the supports are given. 700 N 800 N SOLUTION A, 566 N 60 60 The truss will be analyzed in the following sequence: 30° 30 Joint E, Fig. 3-21b. Note that simultaneous solution of equations is avoided by the x, y axes orientation. 3m 3 m E,-764 N A, 502 N (a)arrow_forward
- 7.37 and 7.38 For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maximum absolute values of the shear and bending moment. Fig. P7.37 6 kips 12 kips с 2 ft D 2 ft 2 ft E 4.5 kips 2 ft Barrow_forward11.103 Members of the truss shown consist of sections of aluminum pipes with the cross-sectional areas indicated. Using E = 70 GPa, deter- mine the vertical deflection of joint D. Members AB, AC, AD, and CE: A = 500 mm²; other members: A = 1000 mm². 40 kN E 1.5 m Co 0.6 m B | A -0.8 m→-0.8 m- Fig. P11.103arrow_forward
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