Connect 1-Semester Access Card for Mechanics of Materials
7th Edition
ISBN: 9780077625207
Author: Ferdinand P. Beer, E. Russell Johnston Jr., John T. DeWolf, David Mazurek
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 1.2, Problem 17P
When the force P reached 1600 lb, the wooden specimen shown failed in shear along the surface indicated by the dashed line. Determine the average shearing stress along that surface at the time of failure.
Fig. P1.17
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PART 2:
Determine the shear force acting at each of the following locations:
(a) x = 0+ ft (i.e., just to the right of support A)
(b) x = 14.0 ft (i,e., at point B.)
(c) x = 20.5- ft (i.e., just to the left of the support C)
(d) x = 20.5+ ft (i.e., just to the right of the support (C)
(e)x=27.5ft
Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.
My Answers:
Correct
(a) V= 105.823 kips
(b)V= -48.177 kips
(c) V= -119.677 kips
(d)V= 88 kips
(e) V= 10.9998 kips
PART 3:
Determine the bending moment acting at each of the following locations:
(a) x = 14.0- ft (i.e., just to the left of point B.)
(b) x = 14.0+ ft(i.e., just to the right of point B.)
(c) x = 20.5 ft (i.e. at point C)
(d)x=27.5ft
Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.
My Answers:
Correct
(a) M = 403.522 kips-ft
(b) M = 193.522 kips-ft
(c) M = -352.0035 kips-ft
(d) M =…
Two wooden planks, each 1212 in. thick and 9 in. wide, are joined by the dry mortise joint shown. Knowing that the wood used shears off along its grain when the average shearing stress reaches 1.8 ksi, determine the magnitude P of the axial load that will cause the joint to fail.
The magnitude P of the axial load that will cause the joint to fail is kips.
Q .: Determine the force necessary to punch a 10 mm dia. Hole in a 20 mm thick mild steel plate, if the shearing strength of mild steel is 10 N / mm2. Also, state the nature and magnitude of the stress in the punch.
Chapter 1 Solutions
Connect 1-Semester Access Card for Mechanics of Materials
Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - A strain gage located at C on the surface of bone...Ch. 1.2 - Two brass rods AB and BC, each of uniform...Ch. 1.2 - Each of the four vertical links has an 8 36-mm...Ch. 1.2 - Link AC has a uniform rectangular cross section 18...Ch. 1.2 - Three forces, each of magnitude P = 4 kN, are...Ch. 1.2 - Link BD consists of a single bar 1 in. wide and 12...
Ch. 1.2 - For the Pratt bridge truss and loading shown,...Ch. 1.2 - The frame shown consists of four wooden members,...Ch. 1.2 - An aircraft tow bar is positioned by means of a...Ch. 1.2 - Two hydraulic cylinders are used to control the...Ch. 1.2 - Determine the diameter of the largest circular...Ch. 1.2 - Two wooden planks, each 12 in. thick and 9 in....Ch. 1.2 - When the force P reached 1600 lb, the wooden...Ch. 1.2 - A load P is applied to a steel rod supported as...Ch. 1.2 - The axial force in the column supporting the...Ch. 1.2 - Three wooden planks are fastened together by a...Ch. 1.2 - A 40-kN axial load is applied to a short wooden...Ch. 1.2 - An axial load P is supported by a short W8 40...Ch. 1.2 - Link AB, of width b = 2 in. and thickness t=14...Ch. 1.2 - Determine the largest load P that can be applied...Ch. 1.2 - Knowing that = 40 and P = 9 kN, determine (a) the...Ch. 1.2 - The hydraulic cylinder CF, which partially...Ch. 1.2 - For the assembly and loading of Prob. 1.7,...Ch. 1.2 - Two identical linkage-and-hydraulic-cylinder...Ch. 1.5 - Two wooden members of uniform rectangular cross...Ch. 1.5 - Two wooden members of uniform rectangular cross...Ch. 1.5 - The 1.4-kip load P is supported by two wooden...Ch. 1.5 - Two wooden members of uniform cross section are...Ch. 1.5 - A centric load P is applied to the granite block...Ch. 1.5 - A 240-kip load P is applied to the granite block...Ch. 1.5 - A steel pipe of 400-mm outer diameter is...Ch. 1.5 - A steel pipe of 400-mm outer diameter is...Ch. 1.5 - A steel loop ABCD of length 5 ft and of 38-in....Ch. 1.5 - Link BC is 6 mm thick, has a width w = 25 mm, and...Ch. 1.5 - Link BC is 6 mm thick and is made of a steel with...Ch. 1.5 - Members AB and BC of the truss shown are made of...Ch. 1.5 - Members AB and BC of the truss shown are made of...Ch. 1.5 - Link AB is to be made of a steel for which the...Ch. 1.5 - Two wooden members are joined by plywood splice...Ch. 1.5 - For the joint and loading of Prob. 1.43, determine...Ch. 1.5 - Three 34-in.-diameter steel bolts are to be used...Ch. 1.5 - Three steel bolts are to be used to attach the...Ch. 1.5 - A load P is supported as shown by a steel pin that...Ch. 1.5 - A load P is supported as shown by a steel pin that...Ch. 1.5 - A steel plate 14 in. thick is embedded in a...Ch. 1.5 - Determine the factor of safety for the cable...Ch. 1.5 - Link AC is made of a steel with a 65-ksi ultimate...Ch. 1.5 - Solve Prob. 1.51, assuming that the structure has...Ch. 1.5 - Each of the two vertical links CF connecting the...Ch. 1.5 - Solve Prob. 1.53, assuming that the pins at C and...Ch. 1.5 - In the structure shown, an 8-mm-diameter pin is...Ch. 1.5 - In an alternative design for the structure of...Ch. 1.5 - Prob. 57PCh. 1.5 - The Load and Resistance Factor Design method is to...Ch. 1 - In the marine crane shown, link CD is known to...Ch. 1 - Two horizontal 5-kip forces are applied to pin B...Ch. 1 - For the assembly and loading of Prob. 1.60,...Ch. 1 - Two steel plates are to be held together by means...Ch. 1 - A couple M of magnitude 1500 N m is applied to...Ch. 1 - Knowing that link DE is 18 in. thick and 1 in....Ch. 1 - A 58-in.-diameter steel rod AB is fitted to a...Ch. 1 - In the steel structure shown, a 6-mm-diameter pin...Ch. 1 - Prob. 67RPCh. 1 - A force P is applied as shown to a steel...Ch. 1 - The two portions of member AB are glued together...Ch. 1 - The two portions of member AB are glued together...
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