LINUX+ AND LPIC-1 GDE.TO LINUX CERTIF.
5th Edition
ISBN: 9781337569798
Author: ECKERT
Publisher: CENGAGE L
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Chapter 12, Problem 1DE
Explanation of Solution
Number of hosts per network:
The default subnet mask of class A is 255.0.0.08.
The IP address is 32 bits.
In this problem, we take 4 bits from the host and add it to network bits.
So,
8 + 4 = 12 bits.
Therefore, the mask bit is = 12.
Consider each octet has 8 bits
In this, we take 8 bits from the 1st octet and 4 bit from the 2nd octet so it can be used in 11 departments.
The remaining bits are
4 bits+ 8 bits+ 8 bits= 20 bits...
Explanation of Solution
Five range of addresses:
The first 5 range of addresses that can be assigned to different departments are,
| SUBNET | RANGE OF HOST | SUBNET SIZE | BROADCAST |
| 100.0.0.0 | 100.0.0.1 TO 100.15.255.254 | 1048574 | 100.15.255.255 |
| 100... |
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Students have asked these similar questions
Assuming that your company uses the Class A network 100.0.0.0/8, with what subnetmask would you need to configure all computers on the network to divide this network11 times to match the company’s 11 departments? How many hosts can you have pernetwork? What are the first five ranges of addresses that you can assign to differentdepartments?
Given the following network: 192.168.10.0/24. Subnet this network with a /25 subnet mask. Answer the following questions:
What is the class of the 192.168.10.0/24?
Using/25, how many networks are available?
Using/25, how many valid hosts per network are available?
Using/25, what is the subnet mask?
Using/25, what is the broadcast address?
You have been allocated a class C network address of 211.1.1.0 and are using the default subnet mask of 255.255.255.0 how may hosts can you have?
Chapter 12 Solutions
LINUX+ AND LPIC-1 GDE.TO LINUX CERTIF.
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