The Physics of Everyday Phenomena
The Physics of Everyday Phenomena
8th Edition
ISBN: 9780073513904
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
Question
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Chapter 12, Problem 1SP

(a)

To determine

The magnitude of the force on 0.02C charge by 0.10C.

(a)

Expert Solution
Check Mark

Answer to Problem 1SP

The magnitude of the force on 0.02C charge by 0.10 C is 4.5×106N.

Explanation of Solution

Given Info: The distance between the charges at A and B is 2m, the charge at point A is +0.10C, the charge at point B is +0.02C.

Write the expression to find the electrostatic force.

F=14πε0q1q2r2

Here,

F is the electrostatic force

q1 is the first charge

q2 is the second charge

r is the distance between the charges

ε0 is the permittivity of free space

Substitute 8.85×1012F/m for ε0, +0.02C for q1, +0.10C for q2, 2m for r to find the electrostatic force.

F=14π(8.85×1012F/m)(+0.02C)(+0.10C)(2m)2=4.5×106N

Conclusion:

Therefore, magnitude of the force on 0.02C charge by 0.10C is 4.5×106N.

(b)

To determine

The magnitude of the force on 0.02C charge by 0.04C.

(b)

Expert Solution
Check Mark

Answer to Problem 1SP

The magnitude of the force on 0.02C charge by 0.04C is 7.2×106N.

Explanation of Solution

Write the expression to find the electrostatic force.

F=14πε0q1q2r2

Substitute 8.85×1012F/m for ε0, +0.02C for q1, 0.04C for q2, 1m for r to find the electrostatic force.

F=14π(8.85×1012F/m)(+0.02C)(0.04C)(1m)2=7.2×106N

Conclusion:

Therefore, magnitude of the force on 0.02C charge by 0.04C is 7.2×106N.

(c)

To determine

The net force exerted on the 0.02C charge by the other two charges.

(c)

Expert Solution
Check Mark

Answer to Problem 1SP

The net force exerted on the 0.02C charge by the other two charges is 2.7×106N to the left direction.

Explanation of Solution

Write the expression to find the net electrostatic force on charge at B.

F=FA+FC

Here,

FA is the force exerted on charge at B by the charge at A

FC is the force exerted on charge at B by the charge at C

F is the net electrostatic force on charge at B

Consider the right direction to be positive.

Substitute 4.5×106N for FA and 7.2×106N for FC to find the electrostatic force.

F=(4.5×106)+(7.2×106N)=2.7×106N

Since, the net force is negative; the direction of the net force will be in the left direction.

Conclusion:

Therefore, the net force exerted on the 0.02C charge by the other two charges is 2.7×106N to the left direction.

(d)

To determine

The direction and magnitude of the electric field at the point B.

(d)

Expert Solution
Check Mark

Answer to Problem 1SP

The direction and magnitude of the electric field at point B is 1.35×108N/C to the left direction.

Explanation of Solution

Write the expression to find the electric field.

E=Fq

Here,

E is the electric field

F is the force exerted on the charge.

q is the charge

Substitute 2.7×106N for F and 0.02C for q to find the electric field at point B.

E=2.7×106N0.02C=1.35×108N/C

The direction of the electric field is in the left direction.

Conclusion:

The direction and magnitude of the electric field at point B is 1.35×108N/C to the left direction.

(e)

To determine

The direction and magnitude of the electrostatic force exerted on the new charge if the 0.02C charge is replaced by a charge of 0.06C.

(e)

Expert Solution
Check Mark

Answer to Problem 1SP

The direction and magnitude of the electrostatic force exerted on the new charge if the 0.02C charge is replaced by a charge of 0.16 C is 8.1×106N to the right direction.

Explanation of Solution

Write the expression to find the electrostatic force.

F=qE

Here,

E is the electric field

F is the force exerted on the charge.

q is the charge

Substitute 1.35×108N/C for E and 0.06C for q to find the electrostatic force point B.

F=(0.06C)(1.35×108N/C)=8.1×106N

Negative sign indicates the direction of the electrostatic force will be in the right direction.

Conclusion:

Therefore, direction and magnitude of the electrostatic force exerted on the new charge if the 0.02C charge is replaced by a charge of 0.06C is 8.1×106N to the right direction.

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Chapter 12 Solutions

The Physics of Everyday Phenomena

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