Chapter 12, Problem 20CQ

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

Chapter
Section

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

# The old rubber boot shown in Figure 12.26 has two leaks. To what maximum height can the water squirt from Leak 1? How does the velocity of water emerging from Leak 2 differ from that of leak 1? Explain your responses in terms of energy.

To determine

The maximum height up to that the water squirt from leak 1 and the way in which the velocity of water emerging from leak 2 is differ from that of leak 1.

Explanation

Formula used:

From projectile motion, the maximum height to which the water squirt from leak 1 is,

â€ƒâ€ƒH=u2sin2Î¸2g

Here,

• H is the height attained by water from the leak 1 .
• u is the velocity of water at the exit.
• Î¸ is the angle of exit.

Calculation:

From the given figure, it is clear that the flow of water from leak 1 follows a horizontal motion.

From projectile motion, the maximum height to which the water squirt from leak 1 is,

â€ƒâ€ƒH=u2sin2Î¸2g

For maximum height water should exit the leak 1 at angle of 45Â°.

Substitute 45Â° for Î¸ in above equation

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