(a)
The current in the loop using graphical method.
(a)
Answer to Problem 25P
The current in the loop, using graphical method, is
Explanation of Solution
Write the ideal diode equation for the current through the diode.
Here,
Substitute
Write the equation for the current in the wire.
Here,
Substitute
Equations (I) and (II) are plotted in figure 1 with the currents along the vertical axis and
The two graphs meet at
Conclusion:
Substitute
Substitute
The currents agree to three digits.
Therefore, the current in the loop, using graphical method, is
(b)
The ohmic resistance of the diode.
(b)
Answer to Problem 25P
The ohmic resistance of the diode is
Explanation of Solution
Write the equation for the ohmic resistance of the diode.
Here,
Conclusion:
Substitute
Therefore, the ohmic resistance of the diode is
(c)
The dynamic resistance of the diode.
(c)
Answer to Problem 25P
The dynamic resistance of the diode is
Explanation of Solution
Write the equation for the dynamic resistance of the diode.
Here,
Rearrange the above equation.
Put equation (I) in the above equation.
Conclusion:
Substitute
Therefore, the dynamic resistance of the diode is
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Chapter 12 Solutions
EBK MODERN PHYSICS
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