Chapter 1.2, Problem 36PPS

(a)

To determine

To find: Add four more points along the line and label them $L,M,N,$ and $O$ .

Answer to Problem 36PPS

The four more points along the line are:

  

Explanation of Solution

Given information:

Use a ruler to draw a line segment $3$ centimeters long. Label the endpoints $A$ and $D.$ Draw two more points along the segment and label them $B$ and $C$ . Draw a second line segment $6$ centimeters long. Label the endpoints $K$ and $P$ .

Calculation:

Therefore, the line segment after drawing and mentioning of $L,M,N,$ and $O$ points is:

  

(b)

To determine

To find: Include a column in your table to record the sum of these measures.

Answer to Problem 36PPS

The table after including a column of sum of the measures is :

$\overline{AD}$
Segment	Length(cm)
$\overline{AB}$	$1.0$
$\overline{BC}$	$1.5$
$\overline{CD}$	$0.5$
$Total$	$3.0$

$\overline{KP}$
Segment	Length(cm)
$\overline{KL}$	$0.5$
$\overline{LM}$	$1.3$
$\overline{MN}$	$1.6$
$\overline{NO}$	$1.9$
$\overline{OP}$	$0.7$
$Total$	$6.0$

Explanation of Solution

Given information:

Use a ruler to measure the length of the line segment between each of the points you have drawn. Organize the length of the segments in $\overline{AD}$ and $\overline{KP}$ in to table.

Calculation:

Therefore, the table after including a column of sum of the measures is :

$\overline{AD}$
Segment	Length(cm)
$\overline{AB}$	$1.0$
$\overline{BC}$	$1.5$
$\overline{CD}$	$0.5$
$Total$	$3.0$

$\overline{KP}$
Segment	Length(cm)
$\overline{KL}$	$0.5$
$\overline{LM}$	$1.3$
$\overline{MN}$	$1.6$
$\overline{NO}$	$1.9$
$\overline{OP}$	$0.7$
$Total$	$6.0$

(c)

To determine

To find: Compare the length determined by your equation to the actual length.

Answer to Problem 36PPS

The compared length by equation is:

  $\begin{array}{l}AD=AB+BC+CD;KP=KL+LM+MN+NO+OP\\ AB+BC+CD=3;KL+LM+MN+NO+OP=6\end{array}$

Explanation of Solution

Given information:

Equation is $\overline{AD}$and $\overline{KP}$. And length is $3$ centimeters.

Calculation:

Consider the equation is:

  $\begin{array}{l}AD=AB+BC+CD;KP=KL+LM+MN+NO+OP\\ AB+BC+CD=3;KL+LM+MN+NO+OP=6\end{array}$

Therefore, length of each segment add up to the length of the whole segment.

  $AB+BC+CD=3;KL+LM+MN+NO+OP=6$