Campbell Biology in Focus; Modified Mastering Biology with Pearson eText -- ValuePack Access Card -- for Campbell Biology in Focus (2nd Edition)
2nd Edition
ISBN: 9780134433776
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman
Publisher: PEARSON
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Chapter 12.2, Problem 1CC
A white-eyed female Drosophila is mated with a red-eyed (wild-type) male the reciprocal cross of the one shown in Figure 12.4. What
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Vermilion eye color in Drosophila is sex-linked and recessive. What would be the phenotypes of maleand female progenies of a cross between a 6 vermilion female and 6 wild-type (red) male. what is the f1 and f2 generation.
if a reciprocal cross is done containing 6 WT females with 6 mutant males what is the F1 and F2 generation. Do they contain the single gene or double gene?
In Drosophila, the sepia mutation (se, chromosome 3, position 26) results in dark brown eyes, while cinnabar (cn, chromosome 2, position 57.5) results in bright orange-red eyes. True breeding, wild type females are mated with true breeding males homozygous recessive for both traits.
Using Drosophila notation, diagram the P1 and F1 crosses.
P1 F1
Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work.
Phenotype
Females
Males
Overall (♀and ♂)
=1 =1
Part 2
Spotty and Cutie have puppies and 50% of the puppies are unaffected for both traits (not blind and not BHFD). What is
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Chapter 12 Solutions
Campbell Biology in Focus; Modified Mastering Biology with Pearson eText -- ValuePack Access Card -- for Campbell Biology in Focus (2nd Edition)
Ch. 12.1 - Which one of Mendels laws relates to the...Ch. 12.1 - MAKE CONNECTIONS Review the description of meiosis...Ch. 12.1 - WHAT IF? Propose a possible reason that the first...Ch. 12.2 - A white-eyed female Drosophila is mated with a...Ch. 12.2 - Neither Tim nor Rhoda has Duchenne muscular...Ch. 12.2 - MAKE CONNECTIONS Consider what you learned about...Ch. 12.3 - When two genes are located on the same chromosome,...Ch. 12.3 - For each type of offspring of the testcross in...Ch. 12.3 - WHAT IF? Genes A, B, and C are located on the same...Ch. 12.4 - About 5% of individuals with Down syndrome have a...
Ch. 12.4 - WHAT IF? The ABO blood type locus has been mapped...Ch. 12.4 - MAKE CONNECTIONS The gene that is activated on the...Ch. 12.4 - Women born with an extra X chromosome (XXX) are...Ch. 12 - A man with hemophilia (a recessive, sex-linked...Ch. 12 - Pseudohypertrophic muscular dystrophy is an...Ch. 12 - A space probe discovers a planet inhabited by...Ch. 12 - Using the information from problem 3, scientists...Ch. 12 - A man with red-green color blindness (a recessive,...Ch. 12 - You design Drosophila crosses to provide...Ch. 12 - A wild-type fruit fly (heterozygous for gray body...Ch. 12 - Assume that genes A and B are 50 map units apart...Ch. 12 - Prob. 9TYUCh. 12 - SCIENTIFIC INQUIRY DRAW IT Assume you are mapping...Ch. 12 - FOCUS ON EVOLUTION Crossing over is thought to be...Ch. 12 - FOCUS ON INFORMATION The continuity of life is...Ch. 12 - SYNTHESIZE YOUR KNOWLEDGE Butterflies have an X-Y...
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- In Drosophila, the brown mutation (bw, chromosome 2, position 104.5) results in brown eyes, while miniature (min, chromosome X, position 36.1) results in wings that are 2/3 the length of wild type. True breeding, wild type females are mated with true breeding males with brown eyes and miniature wings. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1 =1arrow_forwardIn Drosophila,, the curled mutation (cu, chromosome 3, position 50.0) results in wings that curl up, while ebony (e, chromosome 3, position 70.7) results in a dark body. True breeding, wild type females are mated with true breeding males with curled wings and ebony bodies. Considering Drosophila notation, which of the following correctly diagrams the F1 cross? X X 3+ cu e + X X e + + + + + cu e + O + ■ 3+ X X X X Y Y + + ■ cu cu cu ' + ■ cu ■ ' + e + e e e e e + cu +arrow_forwardIn Drosophila, the dominant Bar mutation (B, chromosome X, position 57) results in thin bar- shaped eyes, while the recessive singed (sn, chromosome X, position 21) results burnt looking bristles. True breeding, wild type females are mated with true breeding males with Bar eyes and singed bristles. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1 =1arrow_forward
- In Drosophila fruit flies, the genes for warped wings (dwp), rumpled bristles (rmp), and pallid wings (pld) are linked. A trihybrid female for all three allleles is crossed with homozygous recessive male for all three alleles and the offspring obtained showed the following phenotypes: 3 pld rmp dwp 428 pld rmp + 427 + + dwp 48 + rmp + 47 pld + dwp 23 pld + + 2 + + + 22 + rmp dwp What is the order and map distance between these three alleles?arrow_forwardYou have been given a virgin Drosophila female. You notice that the bristles on her thorax are much shorter than normal. You mate her with a normal male (with long bristles) and obtain the following F1 progeny1 3 short-bristled females, 1 3 long-bristled females, and 1 3 long-bristled males. A cross of the F1 long-bristled females with their brothers gives only long-bristled F2. A cross of short-bristled females with their brothers gives 1 3 short-bristled females, 1 3 long-bristled females, and 1 3 long-bristled males. Provide a genetic hypothesis to account for all these results, showing genotypes in every cross.arrow_forwardIn Drosophila, a cross was made between a yellow-bodied male with vestigial wings and a wild-type (WT) female(brown body and normal wings). The F1 generation consisted of WT males and WT females. The F1 males and females were crossed, and the F2 progeny consisted of 16 yellow males with vestigial wings, 48 yellow males with WT wings, 15 brown males with vestigial wings, 49 WT males, 31 brown females with vestigial wings, and 97 WT females. Based on these results, explain the inheritance of the two genes (i.e. autosomal or sex-linked, dominant or recessive).arrow_forward
- You cross a true breeding, yellow-bodied, male fruit fly to a true breeding, wild-type, female fly and observe that all the progeny have a wild- type body colour. If you set the reciprocal cross, you notice that all the female flies have a wild-type body colour and that all the male flies have yellow bodies. What can you conclude regarding the gene that determines body colour (yellow) in Drosophila? Select one: O a. The yellow gene assorts independently. cross out O b. A mutant yellow gene is lethal. cross out O c. Nothing can be concluded regarding the gene that determines body colour in Drosophila. cross out O d. The yellow gene is sex-linked. O e. The yellow gene is linked to the centromere. cross out cross outarrow_forwardVermillion eye color in Drosophila sp. is a sex-linked recessive trait. What phenotype would be found in this progeny of a cross between a vermillion female and a wild type male?arrow_forwardMiniature wings (Xm) in Drosophila result from an X-linked allele that is recessive to the allele for long wings (X*). Give the genotypes of the parents in the following cross: Male parent Female parent Male offspring Female offspring 231 long, 250 miniature Long Long 560 long O male: Xm/Y and female X* /X* male: X* / Y and female Xm /x O male: X* /Y and female X* /X* male: Xm/Y and female Xm /x+arrow_forward
- The genes for mahogany eyes and ebony body are approximately 18 map units apart on chromosome III in Drosophila. Assume that a mahogany-eyed female was mated to an ebony-bodied male, and the resulting F1 phenotypically wild-type females were mated to mahogany-ebony males. Of 942 offspring, what would be the expected phenotypes and in what numbers would they be expected?arrow_forwardIn Drosophila, ebony body colour is produced by a recessive gene a and wild-type (gray) body colour by its dominant allele a+. Vestigial wings are governed by a recessive gene vg, and normal wing size (wild type) by its dominant allele vg+. If wild-type dihybrid flies are crossed and produce 256 progeny, how many of these progeny flies are expected in each phenotypic class?arrow_forwardIn the fruit fly Drosophila melanogaster, the following genes and mutations are known:Wing size: recessive allele for tiny wings t; dominantallele for normal wings T.Eye shape: recessive allele for narrow eyes n;dominant allele for normal (oval) eyes N.For each of the four following crosses, give thegenotypes of each of the parents.Male FemaleWings Eyes Wings Eyes Offspring1 tiny oval × tiny oval 78 tiny wings, oval eyes24 tiny wings, narrow eyes2 normal narrow × tiny oval 45 normal wings, oval eyes40 normal wings, narrow eyes38 tiny wings, oval eyes44 tiny wings, narrow eyes3 normal narrow × normal oval 35 normal wings, oval eyes29 normal wings, narrow eyes10 tiny wings, oval eyes11 tiny wings, narrow eyes4 normal narrow × normal oval 62 normal wings, oval eyes19 tiny wings, oval eyesarrow_forward
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