ORGANIC CHEMISTRY-PRINT COMPANION (LL)
4th Edition
ISBN: 9781119659594
Author: Klein
Publisher: WILEY
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Chapter 12.4, Problem 11ATS
Interpretation Introduction
Interpretation:
The given reaction is the conversion of ketones to alcohol. It must be determined whether the ring has been oxidized or reduced.
Concept introduction:
It is done by calculating the oxidation state of the atoms. If there is an increase in the charge on any atom, it is said to be oxidized. If there is a decrease in the oxidation state of the atom, it is said to be reduced. The oxidation state of the carbon on which the change has occurred must be calculated by cleaving the bonds between carbon and the atom to which it is attached.
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Students have asked these similar questions
None
Use the following atomic weights and quantities to calculate the overall % yield of
tetraphenylcyclopentadienone. Remember that your yield must be based on the limiting
reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give
only two significant digits in your answer. If after rounding the answer is a whole number, do not
include a decimal point.
C = 12, H = 1, K = 39, O = 16
benzil +
dibenzyl
ketone
potassium
+
→ tetraphenylcyclopentadienone
hydroxide
formula
formula
weight
grams
2.314
7.231
3.857
3.173
moles
Answer:
%
yield
Use the following atomic weights and quantities to calculate the overall % yield of tetraphenylcyclopentadienone. Remember that your yield must be based on the
limiting reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding
the answer is a whole number, do not include a decimal point.
C = 12, H = 1, K = 39, O = 16
formula
formula weight
grams
moles
Answer:
benzil + dibenzyl ketone + potassium hydroxide
tetraphenylcyclopentadienone
4.135
8.646
1.140
% yield
6.956
Chapter 12 Solutions
ORGANIC CHEMISTRY-PRINT COMPANION (LL)
Ch. 12.1 - Prob. 1LTSCh. 12.1 - Prob. 1PTSCh. 12.1 - Prob. 2ATSCh. 12.1 - Prob. 3CCCh. 12.2 - Prob. 4CCCh. 12.3 - Prob. 8CCCh. 12.3 - Prob. 9CCCh. 12.4 - Prob. 3LTSCh. 12.4 - Prob. 10PTSCh. 12.4 - Prob. 11ATS
Ch. 12.4 - Prob. 4LTSCh. 12.4 - Prob. 12PTSCh. 12.4 - Prob. 13ATSCh. 12.6 - Prob. 14CCCh. 12.6 - Prob. 5LTSCh. 12.6 - Prob. 15PTSCh. 12.6 - Prob. 16PTSCh. 12.7 - Prob. 18CCCh. 12.9 - Prob. 6LTSCh. 12.9 - Prob. 19PTSCh. 12.9 - Prob. 20ATSCh. 12.9 - Prob. 21CCCh. 12.10 - Prob. 7LTSCh. 12.10 - Prob. 22PTSCh. 12.10 - Prob. 23ATSCh. 12.13 - Prob. 8LTSCh. 12.13 - Prob. 24PTSCh. 12.13 - Prob. 25ATSCh. 12.13 - Prob. 26CCCh. 12.13 - Prob. 9LTSCh. 12.13 - Prob. 27PTSCh. 12.13 - Prob. 28ATSCh. 12 - Prob. 29PPCh. 12 - Prob. 30PPCh. 12 - Prob. 31PPCh. 12 - Prob. 32PPCh. 12 - Prob. 33PPCh. 12 - Prob. 34PPCh. 12 - Prob. 35PPCh. 12 - Prob. 36PPCh. 12 - Prob. 37PPCh. 12 - Prob. 38PPCh. 12 - Prob. 39PPCh. 12 - Prob. 40PPCh. 12 - Prob. 41PPCh. 12 - Prob. 42PPCh. 12 - Prob. 43PPCh. 12 - Prob. 44PPCh. 12 - Prob. 45PPCh. 12 - Prob. 46PPCh. 12 - Prob. 47PPCh. 12 - Prob. 48PPCh. 12 - Prob. 49PPCh. 12 - Prob. 50PPCh. 12 - Prob. 51PPCh. 12 - Prob. 52PPCh. 12 - Prob. 53ASPCh. 12 - Prob. 54ASPCh. 12 - Prob. 55ASPCh. 12 - Prob. 62IPCh. 12 - Prob. 64IPCh. 12 - Prob. 65IPCh. 12 - Prob. 66IPCh. 12 - Prob. 67IPCh. 12 - Prob. 68IPCh. 12 - Prob. 69IPCh. 12 - Prob. 74IP
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