Chapter 12.5, Problem 1AGP

To determine

The lateral and surface area of the prism.

Answer to Problem 1AGP

The lateral is $L=6.48m^2$

The surface of area is $S=10.12m^2$

Explanation of Solution

Given:

Concept Used:

Lateral :

  $2\left(length+breadth\right)\times height$

Surface Area:

  $2\times length\times breadth\times height$

Calculation:

  $L=Ph$

  $\begin{array}{l}=2\left(1.3+1.4\right)\left(1.2\right)\\ =2\left(2.7\right)\left(1.2\right)\\ =6.48\end{array}$

Surface of Area:

  $S=Ph+2B$

  $\begin{array}{l}=6.48+2\left(1.3\right)\left(1.4\right)\\ =6.48+3.64\\ =10.12\end{array}$

Conclusion:

Hence, the lateral is $L=6.48m^2$

The surface of area is $S=10.12m^2$