Chapter 12.8, Problem 69SR

To determine

Calculate the amplitude and period of the function. Also draw the graph.

Answer to Problem 69SR

The amplitude and period is $2\&2\pi$ .

Explanation of Solution

Given: It is given in the question that the equation is $y=2\cos \theta$ .

Concept Used:

In this, use the concept of general equation of cosine $y=a\cos b\theta$ where a is amplitude and $\frac{2\pi }{\left|b\right|}$ is the period.

Calculation: Here, the given equation is $y=2\cos \theta$

Now, $a=2$ so the amplitude is $2$ .

Since, b is $1$ so the period is $\frac{2\pi }{\left|b\right|}=\frac{2\pi }{\left|1\right|}=2\pi$

The graph of the function is:

  

Conclusion:

The amplitude and period is $2\&2\pi$ .