Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 13, Problem 13.12P
To determine
Find the critical depth of the excavation.
Find the inclination of the failure plane with respect to the horizontal.
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A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.
Consider a slope given below with 10 slices, which has a circular failure surface. Each slice has 5 meters wide, and the weight of each slice was estimated on the basis of average height and a unit weight of soil ? = 16 kN/m3. The shear strength of the soil is assumed to be ? = 20 kPa and ? = 20°. The pertinent data for these ten slices is given in the table below.
a) Determine the factor of safety using Janbu’s simplified method by assuming the initial ?? = ?. ?.
b) Discuss how the factor of safety (stability of the Slope) will change due to the rainfall. You start to consider what environmental conditions will change first.
A cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal.
The Previous explorations showed that a rock layer was located at a depth of 14 m.
Given that,
c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- A 45° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties Cu= 50 kN/m², qu=0° and y = 19 kN/m³ Determine the factor of safety. [Take area of wedge = 39 m²]arrow_forwardA rectangular channel 5.8 m wide by 1.4 m deep was laid to have a hydraulic slope of 0.001. Using n = 0.013. 1. What is its yield in cubic meter per second? 2. What savings in earth excavation could be realized by using most economical proportion? 3. What savings in lining per meter length could be realized by using most economical proportion?arrow_forwardQ.4 A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having strength parameters c = 60 kN/m2 , Ø = 0, and ɣ = 19 kN/m3 . Determine the factor of safety for the trial failure surface shown in Fig. 4arrow_forward
- A rectangular channel 5.8 m wide by 1.4 m deep was laid to have a hydraulic slope of 0.001. Using n = 0.013. (a) What is its yield in cubic meter per second? (b) What savings in earth excavation could be realized by using most economical proportion? (c) What savings in lining per meter length could be realized by using most economical proportion?arrow_forwardA vertical cut is made through a homogeneous soil mass (c=20 kPa,ϕ=20°,γ=16.50 ?? ?3 ⁄ ). Estimate thesafe depth of the cut, taking a factor of safety of 2 using Culmann’s methodarrow_forwardA cut is made into a homogeneous soil as depicted in the figure below, at an angle of 60° with the horizontal. Calculate the resisting shear force in kN along the failure plane given that the shear force applied by the overlying soil wedge is 120 kN. The failure plane is at an angle of 40° from the horizontal direction and the ground water level is below this plane. Assume drained conditions for this question.arrow_forward
- Q.3. A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 19 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forward5. Saturated silty clay encountered in a deep excavation is found to have a water content of 28%. Determine unit weight of the clay in kN/m3. Assume Gs=2.7arrow_forward(Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forward
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