(a) Interpretation: The light which has a higher energy is to be predicted. Concept introduction: The energy of a photon is directly proportional to its frequency ( E = h v ) . Frequency and wavelength are inversely proportional to each other ( v = c /λ ) . Therefore, there is an inverse relationship between energy and wavelength.
(a) Interpretation: The light which has a higher energy is to be predicted. Concept introduction: The energy of a photon is directly proportional to its frequency ( E = h v ) . Frequency and wavelength are inversely proportional to each other ( v = c /λ ) . Therefore, there is an inverse relationship between energy and wavelength.
Solution Summary: The author explains that the energy of a photon is directly proportional to its frequency (E=hv).
Interpretation: The light which has a higher energy is to be predicted.
Concept introduction: The energy of a photon is directly proportional to its frequency (E=hv). Frequency and wavelength are inversely proportional to each other (v=c/λ). Therefore, there is an inverse relationship between energy and wavelength.
Interpretation Introduction
(b)
Interpretation: The light which has a higher energy is to be predicted.
Concept introduction: The energy of a photon is directly proportional to its frequency (E=hv). Frequency and wavelength are inversely proportional to each other (v=c/λ). Therefore, there is an inverse relationship between energy and wavelength.
Interpretation Introduction
(c)
Interpretation: The light which has a higher energy is to be predicted.
Concept introduction: The energy of a photon is directly proportional to its frequency (E=hv). Frequency and wavelength are inversely proportional to each other (v=c/λ). Therefore, there is an inverse relationship between energy and wavelength.
what is the frequency of light in Hz, with a wavelength of 489.1 nm? USE CORRECT ROUNDING AND SIG FIGS
1.) A local FM radio station broadcasts at an energy of 6.04×10-29 kJ/photon. Calculate the frequency at which it is broadcasting.Frequency = __________ MHz (1 MHz = 106 sec -1)
2.)A local FM radio station broadcasts at a frequency of 96.0 MHz.Calculate the energy of the frequency at which it is broadcasting.Energy =__________ kJ/photon(1 MHz = 106 sec -1)
How many kJ (kilojoules) would be in 2.00 moles of green light (λ = 550 nm) photons?