Concept explainers
he following demonstration takes place in a two-step process:
rst, solid calcium carbide
Write the balanced equations for each reaction that is occurring, including all phases.
If a
Now imagine that the final gases produced are collected in a large bulkier and allowed to cool to room temperature. Using the information from part b (
(a)
Interpretation:
The balance chemical equation for the combustion of ethyne and reaction of calcium carbide to produce ethyne.
Concept Introduction:
When the number of atoms of an element on the product side and on the reactant side is equal then such reaction is said to be a balanced chemical equation.
Answer to Problem 140AP
The balanced chemical reaction is given as:
Explanation of Solution
The balance equation indicates that all the number of same atoms must be equal at both sides. Hence we have to write the reactants and products of the reaction and balance each atom at both sides.
In this reaction equation, number of C and Ca is balanced at both sides. Hence we have to balance H and O. To balance H; add 2 as coefficient with H2 O that changes the equation as;
Now O and H both are balanced hence it is a balance equation.
Similarly in second reaction equation;
Let’s balance Carbon at both sides;
Now we have to balance H and O at both sides. To balance O, add 5 as coefficient with O2 and 2 as coefficient with H2 O.
(b)
Interpretation:
Identify the limiting reactant if 100.0- g sample of calcium carbide is initially reacted with 50.0 g of water.
Concept Introduction:
The reactant that forms less amount of product is called as limiting reagent and which limits the reaction and determine the amount of product formed.
Answer to Problem 140AP
Water forms less amount of ethyne so water is limiting reagent.
Explanation of Solution
Molar mass of CaC2 = 64.09 g/mol
Molar mass of H2 O = 18.0 g/mol
Mass of CaC2 = 100 g
Mass of H2 O = 50.0 g
Number of moles of CaC2 =
Number of moles of water =
According to balance chemical equation, 1 mole of ethyne is formed by 2 moles of H2 O and 1 mole of ethyne is formed by 1 mole of calcium carbide.
Hence, H2 O forms less amount of ethyne so water is limiting reagent.
(c)
Interpretation:
The volume of carbon dioxide gas which is produced in the balloon at a pressure of 1.00 atm and 25° C.
Concept Introduction:
The ideal gas equation is given by:
PV = nRT
Where, P = pressure
V = volume
n = number of moles
T = temperature
R = gas constant
By knowing the value of pressure, temperature and number of moles, one can identify the value of volume.
Answer to Problem 140AP
Volume of carbon dioxide produced is 68.01 L.
Explanation of Solution
Given information:
- P = 1 atm.
- T = 25 °C = 25+373 = 298 K.
- n = 2.78 moles (from part b).
- R = 0.0821 L.atm / k.mol.
The given reaction is
Put the given values in ideal gas equation.
PV = nRT
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Chapter 13 Solutions
Introductory Chemistry
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