Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Chapter 13, Problem 22E
Interpretation Introduction

(a)

Interpretation:

The electron-pair geometry for the molecules, PCl3, and SeOF2 is to be explained and the Lewis diagram and wedge-and-dash diagram for the molecules are to be drawn.

Concept introduction:

The electron pairs in Lewis diagrams repel each other in real molecule and thus they distribute themselves in positions around the central atoms that are as far away from one another. This arrangement of electron pairs is called electron-pair geometry. The electron pairs may be shared in covalent bond, or they may be lone pairs.

Expert Solution
Check Mark

Answer to Problem 22E

The Lewis diagrams for PCl3, and SeOF2 are shown as below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  1 and Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  2

The wedge-and-dash diagrams for PCl3, and SeOF2 are shown as below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  3 and Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  4

The electron pair geometry for both molecules is tetrahedral.

Explanation of Solution

To write the Lewis diagram for a compound first the number of valence electrons is to be calculated. In the molecule, PCl3, phosphorous has five valence electrons and each chlorine has seven valence electrons. The total number of valence electron for the molecule PCl3 is calculated below.

Totalnumberofvalenceelectron=(5+3×7)e=26e

Similarly, in the molecule, SeOF2, selenium and oxygen have six valence electrons and each florine has seven valence electron. The total number of valence electron for the molecule SeOF2 is calculated below.

Totalnumberofvalenceelectron=(6+6+2×7)e=26e

The atom which is least electronegative is the central atom. In PCl3 phosphorous is least electronegative element. Therefore, phosphorous is the central atom. Phosphorous is bonded with three chlorine atoms through single bond. In Lewis diagram, each electron is placed around the atom such that the octet rule is obeyed. Therefore, the Lewis diagram of PCl3 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  5

Figure 1

In SeOF2, sulfur is least electronegative element. Therefore, sulfur is the central atom. Sulfur is bonded with two fluorine atoms through single bond and one oxygen atom through double bond. In Lewis diagram, each electron is placed around the atom such that the octet rule is obeyed. Therefore, the Lewis diagram of SeOF2 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  6

Figure 2

The electron-pair geometry depends on the number of electron pairs around the central atoms. In both the molecules PCl3, and SeOF2 there are four electron-pairs around the phosphorous and sulfur atoms. Therefore, the electron pair geometry is tetrahedral for each.

The wedge-and-dash diagram for the molecules PCl3 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  7

Figure 3

The wedge-and-dash diagram for the molecules SeOF2 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  8

Figure 4

Conclusion

The Lewis and wedge-and-dash diagrams for PCl3, and SeOF2 are shown in the Figure 1, Figure 2, Figure 3, aand Figure 4. The electron pair geometry for both molecules is tetrahedral.

Interpretation Introduction

(b)

Interpretation:

The molecular geometry prdicted by the valence shell electron-pair repulsion theory for the molecules PCl3, and SeOF2 is to be explained and the Lewis diagram and wedge-and-dash diagram for the molecules are to be drawn.

Concept introduction:

Molecular geometry is the precise term that is used to describe the shape of molecules and arrangement of atoms around the central atom. The molecular geometry of a molecule is predicted by valence shell electron-pair repulsion theory or in short VSEPR theory. VSEPR theory applies to substances in which a second period element is bonded to two, three, four, or other atoms.

Expert Solution
Check Mark

Answer to Problem 22E

The Lewis diagrams for PCl3, and SeOF2 are shown as below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  9 and Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  10

The wedge-and-dash diagrams for PCl3, and SeOF2 are shown as below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  11 and Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  12

The molecular geometry for both molecules is trygonal pyramidal.

Explanation of Solution

To write the Lewis diagram for a compound first the number of valence electrons is to be calculated. In the molecule, PCl3, phosphorous has five valence electrons and each chlorine has seven valence electrons. The total number of valence electron for the molecule PCl3 is calculated below.

Totalnumberofvalenceelectron=(5+3×7)e=26e

Similarly, in the molecule, SeOF2, selenium and oxygen have six valence electrons and each florine has seven valence electron. The total number of valence electron for the molecule SeOF2 is calculated below.

Totalnumberofvalenceelectron=(6+6+2×7)e=26e

The atom which is least electronegative is the central atom. In PCl3 phosphorous is least electronegative element. Therefore, phosphorous is the central atom. Phosphorous is bonded with three chlorine atoms through single bond. In Lewis diagram, each electron is placed around the atom such that the octet rule is obeyed. Therefore, the Lewis diagram of PCl3 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  13

Figure 1

In SeOF2 sulfur is least electronegative element. Therefore, sulfur is the central atom. Sulfur is bonded with two fluorine atoms through single bond and one oxygen atom through double bond. In Lewis diagram, each electron is placed around the atom such that the octet rule is obeyed. Therefore, the Lewis diagram of SeOF2 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  14

Figure 2

The molecular geometry depends on the number of electron pairs around the central atoms and the number of lone pairs present on the central atom. In the both of the molecules, PCl3, and SeOF2 there are four electron-pairs around the phosphorous and sulfur with one lone pair on the central atoms. Therefore, the geometry would be distorted and change to the molecular geometry as trigonal pyramidal for each.

The wedge-and-dash diagram for the molecules PCl3 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  15

Figure 3

The wedge-and-dash diagram for the molecules SeOF2 is shown below.

Introductory Chemistry: An Active Learning Approach, Chapter 13, Problem 22E , additional homework tip  16

Figure 4

Conclusion

The Lewis and wedge-and-dash diagrams for PCl3, and SeOF2 are shown in the Figure 1, Figure 2, Figure 3, aand Figure 4. The molecular geometry for both molecules is trygonal pyramidal.

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Chapter 13 Solutions

Introductory Chemistry: An Active Learning Approach

Ch. 13 - Prob. 11ECh. 13 - Prob. 12ECh. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - Prob. 15ECh. 13 - Prob. 16ECh. 13 - Prob. 17ECh. 13 - Prob. 18ECh. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 - Prob. 21ECh. 13 - Prob. 22ECh. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Prob. 25ECh. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28ECh. 13 - Prob. 29ECh. 13 - Prob. 30ECh. 13 - Prob. 31ECh. 13 - Prob. 32ECh. 13 - Prob. 33ECh. 13 - Prob. 34ECh. 13 - Prob. 35ECh. 13 - Prob. 36ECh. 13 - Prob. 37ECh. 13 - Prob. 38ECh. 13 - Prob. 39ECh. 13 - Prob. 40ECh. 13 - Prob. 41ECh. 13 - Prob. 42ECh. 13 - Prob. 43ECh. 13 - Prob. 44ECh. 13 - Is the carbon tetrachloride molecule, CCl4, which...Ch. 13 - Prob. 46ECh. 13 - Describe the shapes and compare the polarities of...Ch. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - Prob. 54ECh. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - Prob. 59ECh. 13 - Prob. 60ECh. 13 - Prob. 61ECh. 13 - Prob. 62ECh. 13 - Prob. 63ECh. 13 - Prob. 64ECh. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67ECh. 13 - Classify each of the following statements as true...Ch. 13 - Prob. 69ECh. 13 - Draw Lewis diagrams for these five acids of...Ch. 13 - Prob. 71ECh. 13 - Prob. 72ECh. 13 - Describe the shapes of C2H6 and C2H4. In doing so,...Ch. 13 - Prob. 74ECh. 13 - Prob. 75ECh. 13 - C4H10O is the formula of diethyl ether. The same...Ch. 13 - Prob. 77ECh. 13 - Prob. 78ECh. 13 - Draw Lewis diagrams for water and dihydrogen...Ch. 13 - Prob. 2PECh. 13 - Prob. 3PECh. 13 - Prob. 4PECh. 13 - Prob. 5PECh. 13 - What is the Lewis diagram of butane, C4H10?Ch. 13 - Prob. 7PECh. 13 - Prob. 8PECh. 13 - Prob. 9PECh. 13 - Prob. 10PECh. 13 - In the gas phase, tin (II) chloride is a...Ch. 13 - Prob. 12PECh. 13 - Determine the molecular geometry around each...Ch. 13 - Describe the molecular geometry around each carbon...Ch. 13 - Is the difluoromethane molecule polar or nonpolar?...Ch. 13 - Prob. 1LDRECh. 13 - Prob. 2LDRECh. 13 - Prob. 3LDRECh. 13 - Prob. 4LDRECh. 13 - Prob. 5LDRECh. 13 - Prob. 6LDRECh. 13 - Prob. 7LDRECh. 13 - Prob. 8LDRECh. 13 - Prob. 9LDRECh. 13 - Prob. 10LDRE
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