a. Explanation Given info: The data with appropriate values is given inthe question. Calculation: Step 1: Hypothesis Main effect hypothesis are: For temperature: H 0 : There is no temperature effect. H 1 : There is a temperature effect. For pouring influence: H 0 : There is no pouring influence effect. H 1 : There is a pouring influence effect. Interaction hypothesis is: H 0 : There is no interaction effect between temperature and pouring influence. H 1 : There is an interaction effect between temperature and pouring influence. Step 2: First stage analysis : d f w i t h i n = 5 + 5 + 5 + 5 = 20 And, d f t o t a l = N − 1 Similarly, d f b e t w e e n = n u m b e r _ o f _ t r e a t m e n t − 1 = 4 − 1 = 3 Second stage analysis: S S A = ∑ T 2 r o w n r o w − G 2 N = 120 2 30 + 60 2 30 − 180 2 60 = 60 Similarly, S S A = ∑ T 2 c o l u m n n c o l u m n − G 2 N = 120 2 20 + 40 2 20 + 20 2 20 − 180 2 60 = 280 And, S A × B = S S b e t w e e n _ t r e a t m e n t − S S A − S S B = 340 − 60 − 280 = 0 Now, Step 3: Compute F-ratio First, S S t o t a l = ∑ X 2 − G 2 N = 354 − 60 2 15 = 114 And, b. To determine To explain: The results of ANOVA

Essen.Of Stat. for Behavioral Sci. - Access

8th Edition

ISBN: 9781285592480

Author: GRAVETTER

Publisher: CENGAGE L

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Question

Chapter 13, Problem 22P

To determine

To find: The significance of mean difference using Two-factor ANOVA with α=0.05

To determine

To explain: The results of ANOVA

Expert Solution & Answer

Chapter 13 Solutions

Essen.Of Stat. for Behavioral Sci. - Access

Ch. 13.2 - The F-ratio for the repeated-measures ANOVA is...Ch. 13.2 - A repeated-measures study is used to evaluate the...Ch. 13.2 - Prob. 2LCA Ch. 13.2 - Prob. 3LCA Ch. 13.2 - Prob. 1LCB Ch. 13.2 - Prob. 2LCB Ch. 13.3 - Prob. 1LC Ch. 13.3 - It is impossible to have an interaction unless you...Ch. 13.3 - Prob. 1LCA Ch. 13.3 - Prob. 2LCA

Ch. 13.3 - Prob. 3LCA Ch. 13 - How does the denominator of the F-ratio (the error...Ch. 13 - The repeated-measures ANOVA can be viewed as a...Ch. 13 - A researcher conducts an experiment comparing...Ch. 13 - Prob. 4P Ch. 13 - A researcher uses a repeated-measures ANOVA to...Ch. 13 - A published report of a repeated-measures research...Ch. 13 - A recent study examined how applicants with a...Ch. 13 - One of the primary advantages of a...Ch. 13 - The following data are from an experiment...Ch. 13 - A researcher is evaluating customer satisfaction...Ch. 13 - The following summary table presents the results...Ch. 13 - A recent study indicates that simply giving...Ch. 13 - Prob. 14P Ch. 13 - The endorphins released by the brain act as...Ch. 13 - Prob. 16P Ch. 13 - Explain what happens during each of the two stages...Ch. 13 - The following matrix presents the results from an...Ch. 13 - The following matrix presents the results of a...Ch. 13 - A researcher conducts an independent-measures,...Ch. 13 - Prob. 21P Ch. 13 - Prob. 22P Ch. 13 - Example 13.1 in this chapter described a...Ch. 13 - The following table summarizes the results from a...Ch. 13 - The following data are from a two-factor study...Ch. 13 - Research indicates that paying students to improve...Ch. 13 - A researcher examining the jet lag that people...Ch. 13 - Prob. 2RE Ch. 13 - Briefly describe what is meant by an interaction...Ch. 13 - Most sports injuries are immediate and obvious,...

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