   Chapter 1.3, Problem 32E

Chapter
Section
Textbook Problem

In Exercises 29-34, find an equation of the circle that satisfies the given conditions.32. Center at the origin and passes through (2, 3)

To determine
The equation of the circle that satisfies the given condition.

Explanation

Given:

Center at the Origin and passes through (2,3) .

Formula used:

The distance d between the points (x1,y1) and (x2,y2) is,

d=(x2x1)2+(y2y1)2 (1)

An equation of circle with center C(h,k) and radius r is given by,

(xh)2+(yk)2=r2 (2)

Calculation:

To calculate the radius of circle, find the distance between the two points Origin (0,0) and (2,3) .

Substitute 2 for x2 , 3 for y2 , 0 for x1 and 0 for y1 in equation (1), to calculate the distance

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