UNIVERSE LL W/SAPLINGPLUS MULTI SEMESTER
11th Edition
ISBN: 9781319278670
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 13, Problem 53Q
To determine
The reason for the difference in reflectivity of different parts of Iapetus’s surface. Also provide the probable reason for this difference. It is known that Saturn's largest ring produces an initial difference on Iapetus's surface.
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What is the angular diameter of Saturn (in degrees) as seen from the surface of Dione?
Note:
Necessary data can be found in this Celestial Profile and in this table. Hint: Use the small-angle formula,
angular diameter (in arc seconds)
2.06 ✕ 105
=
linear diameter
distance
Use the small-angle formula to calculate the angular diameter (in degrees) of Saturn (including its rings) (diameter = 9.64 ✕ 105 km) as seen from Earth if Saturn were at the location of the Moon (distance = 384,000 km).
Chapter 13 Solutions
UNIVERSE LL W/SAPLINGPLUS MULTI SEMESTER
Ch. 13 - Prob. 1CCCh. 13 - Prob. 2CCCh. 13 - Prob. 3CCCh. 13 - Prob. 4CCCh. 13 - Prob. 5CCCh. 13 - Prob. 6CCCh. 13 - Prob. 7CCCh. 13 - Prob. 8CCCh. 13 - Prob. 9CCCh. 13 - Prob. 10CC
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- If Saturn had no moons, do you think it would have rings? Why or why not?arrow_forwardWhat is the orbital velocity and period of a ring particle at the outer edge of Saturns A ring? (Hint: Use the formula for circular velocity, Eq. 5-1a. The formula requires input quantities in kg and m.) (Note: The radius of the outer edge of the A ring is 136,500 km.)arrow_forwardIf you were to record the spectrum of Saturn as well as the A ring, you would find light from one edge of the rings red shifted and light from the other edge blueshifted. If you observed a spectral line at a wavelength of 500.000 nm, what difference in wavelength should you expect between the opposite edges of the rings? (Hints: See Problem 9, and use the formula for Doppler shift, Eq. 7-3.)arrow_forward
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