Chapter 13.2, Problem 60STP

To determine

To find : Population standard deviation for given data.

Answer to Problem 60STP

(A)

Explanation of Solution

Given information :

A small business owner hired monthly $\text{5, 14, 6, 8, 12}$ employees for a $\text{5}$ month period. Mean of these data is $\text{9}$ .

Standard deviation $\sigma =\sqrt{\frac{\Sigma {(x_i-\mu )}^2}{N}}$

Calculation :

  $\begin{array}{l}$ \Sigma {(x_i-\mu )}^2={(5-9)}^2+{(14-9)}^2+{(6-9)}^2+{(8-9)}^2+{(12-9)}^2$=4^2+5^2{3}^2+1^2+3^2\\ =16+25+9+1+9=60\\ \sigma =\sqrt{\frac{60}{5}}=3.464,\text{(Round off nearest tenth)}\\ =3.5\text{Option (A)}\end{array}$