Chapter 13.6, Problem 1CYU

To determine

The probability of $6^{th}$ outcome is to be estimated.

Answer to Problem 1CYU

In fraction form, $\text{P(6)=}\frac{\text{3}}{\text{5}}$

In percent form, $\text{P(6)=0}\text{.006\%}$

Explanation of Solution

Given:

The spinner is spun once which showed is below:

  

Calculation:

There are $\text{10}$ total sections on spinner.

So the number of total outcomes becomes $\text{10}$

To find that how many of these $\text{10}$ sections contain a $\text{'6'}$ , As $\text{6}$ is occurred once on the spinner.

  $\text{1}$ Out of $\text{10}$ parts contain $\text{'6'}$

The probability of $6^{th}$ outcome can be calculated by formula,

  $\text{P}\left(6\right)\text{=}\frac{\text{Number of desired outcomes}}{\text{Number of total outcomes}}$

Substituting the values in above formula,

  $\begin{array}{l}\text{P}\left(6\right)\text{=}\frac{\text{6}}{\text{10}}\\ \text{P}\left(6\right)\text{=}\frac{\text{3}}{\text{5}}\end{array}$

Conclusion:

Hence, the probability of $6^{th}$ outcome is $\text{P}\left(6\right)\text{=}\frac{\text{3}}{\text{5}}$