Why does the melting point of hydrocarbons get higher as the number of carbon atoms per molecule increases? (a) An increase in the number of carbon atoms per molecules also means an increase in the density of the hydrocarbon. (b) The induced dipole-induced dipole molecular attractions become stronger. (c) Larger hydrocarbon chains tend to be branched. (d) The molecular mass also increases.
Why does the melting point of hydrocarbons get higher as the number of carbon atoms per molecule increases? (a) An increase in the number of carbon atoms per molecules also means an increase in the density of the hydrocarbon. (b) The induced dipole-induced dipole molecular attractions become stronger. (c) Larger hydrocarbon chains tend to be branched. (d) The molecular mass also increases.
Justify the statement: Polymer molecular weight is
expressed in terms of an average. Calculatethe number
average and weight average molecular weights of polymer
molecules with different degrees of polymerization such as
300, 550, 750 and 900 that are mixed in a molecular ratio
1: 2: 3: 4 in a sample of high polymer of styrene(C6H5
CH= CH2).
Plants grow in many different shapes and sizes. Much of their shape depends on an internal structure that is composed of
carbon-containing molecules such as cellulose and lignin. Plants that have a strong internal structure can grow larger than other
plants because their structure can support their size.
Plants obtain the majority of the carbon necessary for building these structural molecules from -
O air
O microorganisms
O soil
O water
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A loss of an oxide atom results in a 'vacancy'. The presence of these vacancies is
required for conductivity in the solid state.
How many vacancies will be in the doped cell?
Explain how these vacancies allow oxide ions to move through the material.
Chapter 14 Solutions
Modified Mastering Physics with Pearson eText -- Standalone Access Card -- for Conceptual Integrated Science
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The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY