BIG JAVA: LATE OBJECTS
BIG JAVA: LATE OBJECTS
2nd Edition
ISBN: 9781119626220
Author: Horstmann
Publisher: WILEY
Expert Solution & Answer
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Chapter 14, Problem 2RE

Explanation of Solution

Code walkthrough:

The below is the code walkthrough of the selection sort algorithm with the array of different length:

Array length being 0 or 1:

  • When the value of “i” is equal to “0” then “i<a.length-1” is not true.
  • The “for” loop that is present in the sort method will never execute and the array will remain unchanged.

Array length being 2:

  • The “for” loop that is present in the sort will execute once.
  • When the value of “i=0” then “minimumPosition(a,0)” gets called.
  • The “for” loop that is present gets executed from “=i” that is from 1 till less than 2, that is the loop will be executed once.
  • The value of “minPos” is initially set to “0”.
  • If the value of “a[1] is less than a[0]” then the value of “minPos” will be set to “1”.
  • Finally when the method returns the values, two values will be swapped and that will make the array to be sorted...

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Chapter 14 Solutions

BIG JAVA: LATE OBJECTS

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