Concept explainers
From among the isomeric compounds of molecular formula,
Contains only a single peak
Has several peaks including a doublet at
Has several peaks including a triplet at
Has several peaks including two distinct three-proton signals, one of them a triplet at
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- The 13C-NMR spectrum of 3-methyl-2-butanol shows signals at 17.88 (CH3), 18.16 (CH3), 20.01 (CH3), 35.04 (carbon-3), and 72.75 (carbon-2). Account for the fact that each methyl group in this molecule gives a different signal.arrow_forward2) Compound C gave the following proton NMR signals: a) singlet,1.22 ppm, 6H; b) Triplet, 1.85 ppm, 2H, J = 7 Hz; c) triplet, 2.83 ppm, 2H, J = 7 Hz; d) singlet, 7.02 ppm, 4H. Sketch the proton NMR spectrum of compound C and assign the chemical shifts to the protons of the compounds.arrow_forwardCompound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forward
- 1Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forward14. Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forwardThe following is the predicted 1H-NMR spectrum for an unknown compound with molecular formula C6H14O . This compound is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas.arrow_forward
- What compound is represented by the following NMR spectrum? There are 5 signals in the picture I included. They are: A) 7.2 ppm, 5H, multiplet B) 4.8 ppm, 2H, singlet C) 2.6 ppm, 2H, quartet D) 1.2 ppm, 1H, singlet E) 1.1 ppm, 3H, triplet The molecular formula is C9H13Narrow_forwardWhat is the structure of the compound with the formula C8H10O, that shows six signals in its 13C-NMR spectrum, The 1H-NMR spectrum is: 1.98 ppm (1H singlet) 2.82 ppm (2H triplet) 3.80 ppm (2H triplet) 7.22 ppm (5H broad multiplet)arrow_forwardHow many peaks will show up in the H NMR spectrum of the given compound below. Choose one: A. 9 B. 6 C. 5 D. 11arrow_forward
- A compound with molecular formula C5H10O2has the following NMR spectrum. Determine the number of protons giving rise to the signals at 2.0 ppm and 4.0 ppm.arrow_forwardThe compound has a molecular formula of C5H10O and the following 13C spectrum. A proton NMR was measured, but the data was lost except for the fact that it showed three distinct signals: a singlet, a doublet, and a septet, all of which appear between 0 and 3 ppm. Identify the compound, and draw its 1H NMR.arrow_forwardFor the following compound, how many different signals would you expect to see in the 1H NMR spectrum? a) 6 b) 8 c) 10 d) 12arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning