Concept explainers
Interpretation:
The structure of compound Y is to be proposed on the basis of
Concept introduction:
Nuclear Magnetic Resonance (NMR) is one of the most capable analytical techniques used for determining the functional groups and how the atoms are structured and arranged in a molecule.
Few elements, such as
In
spectroscopy, the proton nuclear magnetic resonance
atom within the molecules.
Induced magnetic field consists of electricity generated from movement in a magnetic field.
Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various functional groups.
It depends on the interactions of atoms or molecules with the electromagnetic radiation.
Infrared spectroscopy is most commonly used in the identification of the structure of the compound.
Infrared spectroscopy is the examination of the infrared light interacting with a molecule. The examination can be done in three ways, that is, by measuring absorption, emission, and reflection, and it can also measure the vibration of atoms.
NMR is only used in the observation of isotopes of carbon atoms.
The
signal for protons bonded to substituted benzene rings is between
The IR (infrared) spectra of benzene show the absorption occurring at
bond. Further, the monosubstituted benzene results in the generation of peaks in the range of
group gives a broad peak at
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EBK ORGANIC CHEMISTRY
- Identify products A and B from the given 1H NMR data. Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?arrow_forwardCompound A and compound B both have molecular formula C6H12. Both compounds produce epoxides when treated with a peroxy acid (RCO3H). The epoxide resulting from compound A was treated with aqueous acid (H3O+) and the resulting diol has no chiral centers. Identify the two possible structures for compound A (enter two numbers separated by commas with no spaces, e.g. "1,2") The epoxide resulting from compound B was treated with (H3O*) and the resulting diol was a meso compound. Identify compound B 2 3 potn 7 1 5 6 4 8arrow_forwardIdentify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?arrow_forward
- Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.arrow_forwardTreatment of a hydrocarbon A (molecular formula C9H18) with Br2 in the presence of light forms alkyl halides B and C, both having molecular formula C9H17Br. Reaction of either B or C with KOC(CH3)3 forms compound D (C9H16) as the major product. Ozonolysis of D forms cyclohexanone and acetone. Identify the structures of A–D.arrow_forwardWhat reactions and reagents can be used to make phenol from benzene if electrophilic aromatic substitution reactions are excluded and benzene is the only source of carbon?arrow_forward
- Name the following compounds A and B. How could you distinguish these two molecules by using 1H NMR and IR techniques? Propose an analytical technique to determine the iron content of these compounds. Calculate the mass percentages of C and H of compound B (C: 12.01 g/mol; H: 1.008 g/mol; Fe: 55.845 g/mol).arrow_forwardThe reaction of N−bromosuccinimide with 4−methyl−3−nitroanisole has been reported in the chemical literature. This reaction yields a single product in 95% yield. Identify the product formed from this starting material.arrow_forwardWhen 2-chloropropane treated with NaOH and 1-chloropropane treated with NaOH separately produce two different functional groups. Provide both reactions and explain the two different functional groups produced.arrow_forward
- As a method for the synthesis of cinnamaldehyde (3-phenyl-2-propenal), a chemist treated 3-phenyl-2-propen-1-ol with K2Cr2O7 in sulfuric acid. The product obtained from the reaction gave a signal at δ5 in its 13C NMR spectrum. Alternatively, when the chemist treated 3-phenyl-2-propen-1-ol with PCC in CH2Cl2, the 13C NMR spectrum of the product displayed a signal at δ193.8. (All other signals in the spectra of both compounds appeared at similar chemical shifts.) (a) Which reaction produced cinnamaldehyde? (b) What was the other product?arrow_forwardCompound A has molecular formula C7H15B.. Treatment of compound A with sodium ethoxide yields only one elimination product (compound B) and no substitution products. When compound B is treated with dilute sulfuric acid, compound C is obtained, which has molecular formula C7H160. Draw the structures of compounds A, B, and C.arrow_forwardAn unknown compound A of molecular formula C10H18O reacts with H2SO4 to form two compounds (B and C)of molecular formula C10H16. B and C both react with H2 in the presence of Pd-C to form decalin. Ozonolysis of B forms D, and ozonolysis of C forms a diketone E of molecular formula C10H16O2. Identify the structures of compounds A, B, C, and E.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning