Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 14, Problem 9TYKM
Summary Introduction
To match: The given term “homozygous” with its description.
Introduction: Gregor Johann Mendel is known as “Father of modern genetics”. Genetics is the branch of biology that deals with the study of genes, their inheritance patterns, factors that control them, structure, and function.
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Students have asked these similar questions
A person is heterozygous for the Freckles phenotype (Ff) and also heterozygous for the PTC-tasting phenotype (Tt).
This person's genotype for these two traits is represented as FfTt.
A) How many unique gametes could be produced by this individual if you consider these two traits?
B) List the different allele combinations that could result.
. A man with a blood type AB is married to a woman with blood type A. They have natural children and one adopted child. These are the children with their blood type: Baltazar has blood type A, Melchor has blood type AB and Melchor has blood type O.
a. Who was adopted?
b. What genetic problem is this? (monohybrid, dihybrid or multiple allele)
c. Show the Punnett square.
A man with blood type A and a woman of blood type B have a baby girl of blood type O. The man sues his wife for divorce, on the grounds that it is not possible for the baby to be theirs (since the blood type is not A, B. or AB). Evaluate the lawsuit on the basis of genetics (A, B alleles are co-dominant over the recessive O allele).
IA = A allele IB = B allele iO = O allele
Chapter 14 Solutions
Study Guide for Campbell Biology
Ch. 14 - Fill in the following diagram of a cross of...Ch. 14 - A tall pea plant is crossed with a recessive dwarf...Ch. 14 - A true-breeding tall, purple-flowered pea plant...Ch. 14 - a. In the following cross, what is the probability...Ch. 14 - Prob. 5IQCh. 14 - Consider an example in which the M/m gene (for...Ch. 14 - The height of spike weed is a result of polygenic...Ch. 14 - Consider the following pedigree for the trait...Ch. 14 - a. What is the probability that a mating between...Ch. 14 - If two prospective parents both have siblings who...
Ch. 14 - Prob. 1SYKCh. 14 - How many different types of gametes can be formed...Ch. 14 - Prob. 3SYKCh. 14 - _______ gene Description a. has no effect on...Ch. 14 - _________ allele Description a. has no effect on...Ch. 14 - Prob. 3TYKMCh. 14 - Prob. 4TYKMCh. 14 - __________ dominant allele Description a. has no...Ch. 14 - __________ recessive allele Description a. has no...Ch. 14 - __________ genotype Description a. has no effect...Ch. 14 - Prob. 8TYKMCh. 14 - Prob. 9TYKMCh. 14 - Prob. 10TYKMCh. 14 - Prob. 11TYKMCh. 14 - Prob. 12TYKMCh. 14 - According to Mendels law of segregation, a. there...Ch. 14 - The F2 generation a. has a phenotypic ratio of...Ch. 14 - A 1:1 phenotypic ratio in a testcross indicates...Ch. 14 - Which phase of meiosis is most directly related to...Ch. 14 - After obtaining two heads from two tosses of a...Ch. 14 - The probability of tossing three coins...Ch. 14 - The probability of tossing three coins...Ch. 14 - In the F2 of a dihybrid cross involving two...Ch. 14 - In guinea pigs, the brown coat color allele (B) is...Ch. 14 - A true-breeding dwarf corn plant with red ears is...Ch. 14 - Prob. 11TYKCh. 14 - Prob. 12TYKCh. 14 - Prob. 13TYKCh. 14 - In humans, earwax can be wet or dry. The form of...Ch. 14 - You have blood type B, your mother has blood type...Ch. 14 - Prob. 16TYKCh. 14 - Summer squash are either white or yellow. To get...Ch. 14 - Prob. 2GPCh. 14 - True-breeding tall red-flowered plants are crossed...Ch. 14 - Prob. 4GPCh. 14 - Prob. 5GPCh. 14 - Prob. 6GPCh. 14 - Prob. 7GPCh. 14 - Prob. 8GPCh. 14 - Prob. 9GPCh. 14 - Fur color in rabbits is determined by a single...Ch. 14 - Prob. 11GPCh. 14 - The ability to taste phenylthiocarbamide (PTC) is...Ch. 14 - Prob. 13GPCh. 14 - Prob. 14GPCh. 14 - Prob. 15GPCh. 14 - Prob. 16GPCh. 14 - Imagine that a newly discovered, recessively...Ch. 14 - In mice, black fur (B) is dominant to white (b)....
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- Match column A to Column B 1. Gene 2. Allele 3. Character 4. Dominant Allele 5. Trait 6. Recessive Allele 7. Genotype 8. Phenotype 9. Homozygous 10. Testcross 11. Heterozygous 12. Monohybrid Cross a. Has no effect on phenotype in a heterozygote. b. A variant for a character c. Having two identical alleles for a gene d. A cross between individuals heterozygous for a single character e. An alternative version of a gene f. Having two different alleles for a gene g. A heritable feature that varies among individuals h. An organism's appearance or observable traits i. Determines phenotype in a heterozygote j. A cross between an individual with an unknown genotype and a homozygous recessive k. The genetic makeup of an individual l. A heritable unit that determines a character; can exist in different formsarrow_forwardIn some chickens, the gene for feather color is controlled by codominance. The allele for black is B and the allele for white is W. The heterozygous phenotype is known as erminette (black and white spotted). 10pts a) What is the genotype for black chickens? b) What is the genotype for white chickens? c) What is the genotype for erminette chickens? d) Two erminette chickens were crossed. Show the Punnett square. e) What’s the probability they would have a black chick? ____% f) What’s the probability they would have a white chick? ____% g) What’s the probability they would have erminette chick? ___ %arrow_forwardSince each child of two heterozygous parents has a 1/4 chance of receiving a recessive trait from each parent. A)If the first child is phenotypically recessive, then the next child has 3/4 chance of being phenotypically recessive B)no matter what the first child's phenotype, the next child will have a 1/4 chance of being phenotypically recessiveC)if the first child is phenotypically recessive, then the next child has a 1/2 chance of being phenotypically recessive D)if the first child is phenotypically recessive, then the next child must be phenotypically dominant.arrow_forward
- Heterozygous is when... Choose the right answer: a.) the alleles are different b.) the alleles are absent c.) the alleles are present d.) the alleles are the samearrow_forwardA cross between homozygous purple-flowered and homozygous white-flowered pea plants results in offspring with purple flowers. This demonstrates Group of answer choices a. dominance. b. true-breeding. c. the mistakes made by Mendel. d. the blending model of genetics. e. a dihybrid cross.arrow_forwardAn individual is true breeding for a character if they are _____. A. Heterozygous B. Homozygous dominant C. Homologous D. Homozygous recessivearrow_forward
- If an organism has two different alleles (call the alleles a andb) of a gene,a. its phenotype will be the same as an organism with twoidentical alleles of this gene.b. all of its gametes will contain both the a allele and theb allele.c. it is homozygous for that gene.d. it is heterozygous for that gene.arrow_forwardPhenotype is the allele combinations of an individual that cause traits or diseases. Genotype is the expression of a gene in traits or symptoms. A. Both statements are correct B. Both statements are incorrect C. First statement is Correct, Second is Incorrect D. First statement is Incorrect, Second is Correctarrow_forwardImagine a test cross for an unknown exhibiting 2 traits, where half of the offspring exhibit both dominant traits and the other half exhibits one dominant and one recessive trait. What can you conclude about the unknown? options: A) The unknown is homozygous dominant for both traits. B) The unknown is homozygous recessive for both traits. C) The unknown is heterozygous for both traits. D) The unknown is homozygous for one gene and heterozygous for the other. E) There is not enough information to determine the answer.arrow_forward
- Alleles for Tay-Sachs disease are inherited in an autosomal recessive pattern. Why would two parents with a normal phenotype have a child with Tay-Sachs? a. Both parents are homozygous for a Tay-Sachs allele. b. Both parents are heterozygous for a Tay-Sachs allele. c. New mutations gave rise to Tay-Sachs in the child. d. b or carrow_forwardA heterozygous individual has _______ for a trait being studied. a. the same allele on both homologous chromosomes b. two different alleles of a gene c. a haploid condition, in genetic termsarrow_forwardWhat is the reason for doing a test cross? a. to identify heterozygous individuals with the dominant phenotype b. to determine which allele is dominant and which is recessive c. to identify homozygous recessive individuals in the F2 d. to determine if two genes assort independentlyarrow_forward
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