Finding the Mass of a Lamina In Exercises 3-6, find the mass of the lamina described by the inequalities, given that its density is .
To calculate: The mass of the lamina described by the inequalities given that its density is
, , .
The provided density of lamina is: , , .
Mass of planar lamina is:
The integral of .
The relation from trigonometric identity,
Consider the density function , , .
Here the limit of y is, and that of x .
The given limits for the integral has square root function, so it is easier to solve this problem by
the use of polar coordinates.
First convert the double integral into polar coordinates as:
The limits of the given double integral are:
As y varies from to .
As the equation of circle is and compare with the equation of circle
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