Chapter 14.5, Problem 18PSB

To determine

To construct the geometric mean between $2a$ and $3a$

Explanation of Solution

Given:

The given segment of length $a$

Calculation:

The geometric mean between $2a$ and $3a$ is

  $\begin{array}{l}\sqrt{2a\times 3a}\\ =\sqrt{6a^2}\\ =a\sqrt{6}\end{array}$