Find the minimum value of f ( x ,   y ) =   x 2 + y 2 -  4 x y , subject to the constraint  x   +   y   = 10 ,  by

setting the three partial derivatives (from Question 2) equal to 0 and solving the equations simultaneously for x and y,

To calculate: The critical values x and y by setting the three partial derivatives ∂F∂x, ∂F∂y and ∂F∂λ equal of the objective function F(x,y,λ) of the function f(x,y)=x2+y2−4xy subject to the constraint x+y=10 equal to zero and then solving the equations simultaneously for x and y.

Given Information:

The provided function is f(x,y)=x2+y2−4xy subject to the constraint x+y=10.

Formula used:

According to the Lagrange multipliers method to obtain maxima or minima for a function z=f(x,y) subject to the constraint g(x,y)=0,

(1) Find the critical values of f(x,y) using the new variable λ to form the objective function F(x,y,λ)=f(x,y)+λg(x,y).

(2) The critical points of f(x,y) are the critical values of F(x,y,λ) which satisfies g(x,y)=0.

(3) The critical points of F(x,y,λ) are the points that satisfy ∂F∂x=0, ∂F∂y=0, and ∂F∂λ=0, that is, the points which make all the partial derivatives of zero.

For a function f(x,y), the partial derivative of f with respect to y is calculated by taking the derivative of f(x,y) with respect to y and keeping the other variable x constant. The partial derivative of f with respect to y is denoted by fy.

Power of x rule for a real number n is such that, if f(x)=xn then f′(x)=nxn−1.

Constant function rule for a constant c is such that, if f(x)=c then f′(x)=0.

Coefficient rule for a constant c is such that, if f(x)=c⋅u(x), where u(x) is a differentiable function of x, then f′(x)=c⋅u′(x).

Calculation:

Consider the function, f(x,y)=x2+y2−4xy.

The provided constraint is x+y=10.

According to the Lagrange multipliers method,

The objective function is F(x,y,λ)=f(x,y)+λg(x,y).

Thus, f(x,y)=x2+y2−4xy and g(x,y)=x+y−10.

Substitute x2+y2−4xy for f(x,y) and x+y−10 for g(x,y) in F(x,y,λ)=f(x,y)+λg(x,y)