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MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
5th Edition
ISBN: 9781305581159
Author: Nicholas J. Garber; Lester A. Hoel
Publisher: Cengage Learning US
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Chapter 15, Problem 11P
To determine
(a)
Design speed for the horizontal curve of a two-lane road in mountainous terrain.
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A 5% grade intersects a -3.4% grade at station 41+990 of elevation 42.30 m. Design a vertical summit parabolic curve connecting the two tangent grades to conform with the following safe stopping sight distance specifications.Design Velocity = 60 kphHeight of driver's eye from the road pavement = 1.37 mHeight of an object over the pavement ahead = 100 mm Perception-reaction time = 3/4 sCoefficient of friction between the road and the tires = 0.15
An equal-tangent vertical curve
connects a +3.2 % and a -1.1 %
grade. The PVI is at station
100+20 and elevation 950 ft
and the PVT is at station
105+20. Answer the following
5 questions Question 3 to
Question 7.
The station of the PVC is at:
sta 93+20
sta 95+20
sta 97+20
sta 99+20
sta 105+20
A horizontal curve is designed for a two-lane road in mountainous terrain. The following data are known. Intersection angle: 40 degrees Tangent length: 436.76 feet Station of PI: 2700 = 10.65 fs= 0.12 e = 0.08 Determine the following. (a) Design speed (b) Station of the PC (c) Station of the PT (d) Deflection angle and chord length to the first even 100 ft station.
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MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
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- A horizontal Curve is designed for a two lane mountainous terrain. The following data are known. intersection angle: 40 degrees tangent length: 436.76 ft Station on PI: 2700+10.65 fs=0.12 e=0.08 Find the following Design speed Station of the PC Station of the PT Deflection Angle and chord length to the first even 100 ft stationarrow_forwardYou are required to set up a vertical curve for a highway alignment. Gradient of the backward and forward tangents are +5% and -3%, respectively. The stations of the beginning of the vertical curve (BVC) and the end of the vertical curve (EVC) are 100+00 and 112+00 (ft), respectively. Elevation of EVC is 260.00 ft. Please calculate 1. Station of Point of vertical intersection (PVI). 2. Elevations of the curve at 110+00. 3. Station and elevation of the point in the curve that has the maximum elevation. 4. Tangent offset (distance from the tangent to the curve) at the point calculated in (b).arrow_forward1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']arrow_forward
- 6) A horizontal curve is to be designed on a 2-lane road on a mountainous terrain. The flowingdata are known: Δ= 40 deg, T = 436.76’, station of PI: 2700+10.65, fs = 0.12, and e = 0.08.Determine the following:a) design speedb) station of the PCc) station of the PTd) deflection angle to the first 100’ statione) chord length to the first 100’ stationarrow_forwardA +3% grade intersects a -3.4% grade at station 2+990 of elevation 52.30m. Design a vertical summit parabolic curve connecting the two tangent grades to conform with the following safe specifications: Design velocity = 70kph Height of drivers eye from the road pavement = 1.37m = h, Height of object over the pavement = 650mm = h, Perception – reaction time = 2.5 sec = t Coefficient of friction between the road pavement and the tires = 0.15 = f Brake efficiency = 40% Determine: (a) Length of the curve (b) Station of P.C and P.T. and the location of the highest point of the curve (c) elevation of the highest point of the curve m/s) 2(m)(c0.15)(0.40)+0.03} 70 (v)? 70 SSD = (v)(t) + G m/s)(2.5s) + 3.6 79.01m 2g(f±G) 3.6 = 262.73m CE 31arrow_forwardDetermine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255', Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed=60 mph, max superelevation=8% 8) The station of the NC is: O 8+12.5 8+90 8+92.5 O 11+22.5 O 12+00arrow_forward
- A horizontal curve is to be designed for a two-lane road in mountainous terrain. The following data are known: Intersection angle: 60 degrees, tangent length = 813.10 ft, station of PI: 2,700 + 10.65, fs = 0.12, e = 0.08. Determine the following. The design speed was found to be 65 mph. a) station of the PC (Enter the first answer exactly, and round the second answer to at least one decimal place.) b) station of the PT (Enter the first answer exactly.) c) deflection angle (in degrees) and chord length (in ft) to the first 100 ft stationarrow_forwardIncorrect Question 14 A simple circular curve is specified vwith a 12° degree (arc basis) horizontal curve and e=0.08. A structure is proposed on land on the inside of the curve. Assume the road is on level grade. Determine the minimum distance allowable between the proposed structure and the centerline of the curve such that the current maximum safe speed of the curve would not be reduced. (assume radius = 5001 Use coefficient of side friction = 0.13 86arrow_forward3.48 A horizontal curve is being designed for a new two-lane highway (12-ft lanes). The PI is at station 250 + 50, the design speed is 65 mi/h, and a maximum superelevation of 0.07 ft/ft is to be used. If the central angle of the curve is 38 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT. 3.49 You are nalarrow_forward
- A vertical curve is formed on a two lane undivided highway between the tangents of 1 gradient + 1 Assume the height of driver's eye and height of obstruction and 100 50 as 1.4 m and 0.18 m respectively. Determine the length of vertical curve so formed considering stopping sight distance calculated using the following parameters. Design speed of vehicle = 80 kmph Reaction time = 2.5 sec Down gradient = 2.5% Coefficient of longitudinal friction = 0.38arrow_forwardDetermine variables requested below for a horizontal curve with the following characteristics. Length of curve 1255', Radius 1200', sta of PC 12+00 superelevation rotated about the roadway centerline, 3 lane roadway, 14ft lane width, entire road section normal crown=2%, road design speed%3D60 mph, max superelevation=8% 6) The length in full superelevation, in ft, is: O 790 O 1100 O 1410 O 1875 O 2075arrow_forwardDesign a vertical summit parabolic curve connecting two tangent grades, a 5% grade intersecting a -3.4% grade at station 1 + 990 with an elevation 42.30 meters. The parabolic curve shall conform with the following safe stopping sight distance requirements. Design velocity = 60 kph Height of driver’s eye from the road pavement = 1.37 meters Height of an object over the pavement ahead = 100 mm. Perception/reaction time = 0.75 second Coefficient of friction between the road pavement and the tires = 0.15 Determine the following: Stopping sight distance The length of the curve The elevation of the highest point on curve.arrow_forward
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