PRINCIPLES OF GEOTECH.ENGINEERING >LL+M
9th Edition
ISBN: 9781337583879
Author: Das
Publisher: CENGAGE L
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Question
Chapter 15, Problem 15.1P
To determine
Find the height (H) of the soil-rock interface.
Expert Solution & Answer
Answer to Problem 15.1P
The height of the soil-rock interface is
Explanation of Solution
Given information:
The slope rise at an angle
The unit weight
The angle of friction
The cohesion
The factor of safety
Calculation:
Determine the height of the soil-rock interface using the formula.
Substitute 3.1 for
Thus, the height of the soil-rock interface is
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Students have asked these similar questions
Q.1. Refer to the infinite slope shown in Figure 1. Given: β = 19 ͦ,
ɣ = 20 kN/m3
, Ø = 33 ͦ,
and c’ = 47 kN/m2
. Find the height, H, such that a factor of safety, Fs = 3.1 is maintained
against sliding along the soil-rock interface.
Q.1. Refer to the infinite slope shown in Figure 1. Given: β = 19 ͦ, ɣ = 20 kN/m3
, Ø = 33 ͦ,
and c’ = 47 kN/m2
. Find the height, H, such that a factor of safety, Fs = 3.1 is maintained
against sliding along the soil-rock interface.
Also Determine the thrust on the wall if the water table rises to a level 2 m below the surface
of the sand. The saturated unit weight of the sand is 20 kN/m3
.
An infinite slope consists of bed rock inclined at 15° to the horizontal that is covered by 4 m (measured vertically) soil with ?′=10?N/?2, ?′=24° and ?=19.0?N/?3.a. What is the factor of safety of this slope?b. If there is steady state seepage through the soil, with the water table coinciding with the ground level, what would be the factor of safety? Assume ?sat = 19.0?N/?3.
Chapter 15 Solutions
PRINCIPLES OF GEOTECH.ENGINEERING >LL+M
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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Similar questions
- Figure 2 shows a slope with an inclination of : β = 58 ͦ. If AC represents a trial failure plane inclined at an angle θ = 32 ͦ with the horizontal, determine the factor of safety against sliding for the wedge ABC. Given: H = 6 m; ɣ = 19 kN/m3, Ø =21 ͦ, and c’= 38 kN/m2arrow_forwardGiven an infinite slope with the following properties: γ = 17 kN/m3, H = 5 m, β = 34°, φ = 25° and c = 20 kPa. a. Determine the normal stress. b. Determine the shear stress. c. Determine the factor of safety.arrow_forward3. An infinite slope has shear strength parameters at the interface: c = 30 kPa, φ = 30°, γ = 17 kN/m3 (Assume 1 m strip perpendicular to the paper and 1 m strip along the inclination of the infinite slope). a. If H = 5 m, and β = 20°, find the sliding force. b. If H = 5 m, and β = 20°, find the force that resist sliding on the rock surface. c. If HCR = 8 m, find the minimum angle β so that the slope is stable.arrow_forward
- For the infinite slope shown in Figure 15.46, determine the height, H, for critical equilibrium. Given: β = 27°, γ = 19.5 kN/m3, ϕ′ = 18°, and c′ = 35.9 kN/m3.arrow_forwardA cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the maximum depth in meters up to which the cut could be made?arrow_forward
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