MindTap Engineering, 1 term (6 months) Printed Access Card for Das/Sivakugan’s Principles of Foundation Engineering, 9th
9th Edition
ISBN: 9781337705202
Author: Das, Braja M., SIVAKUGAN, Nagaratnam
Publisher: Cengage Learning
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Chapter 15, Problem 15.5P
To determine
Find the total likely swell beneath the foundation.
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sample of normally consolidated clay was subjected to a consolidated undrained triaxial compression
st that was carried out until the specimen failed at a deviator stress of 50 kN/m?. The pore water
pressure at failure was recorded to be 20 kN/m? and confining pressure of 50 kN/m² was used in the
test. Determine the consolidated undrained friction angle o and drained friction angle ¢cn:
CD
си
A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, σ3 = 250 kN/m² and deviator
stress, (Aod)f = 100 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal
stress o and the shear stress tf on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in
two decimal places.
Q.23
A normally consolidated clay settled by 2cm
when the effective stress was increased
from 100kPa to 200kPa. when the effective
stress is increased to 400kPa then the total
settlement will be
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MindTap Engineering, 1 term (6 months) Printed Access Card for Das/Sivakugan’s Principles of Foundation Engineering, 9th
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- A consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle that the failure plane makes with the major principal axis in degrees. show fbd a.16.3 b.24.72 c.54.74 d.19.47arrow_forwardA consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: O3 = 150 kN/m? (Aoa)f= 130 kN/m? Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress tf on the failure plane d. Determine the effective normal stress on the plane of maximum shear stressarrow_forwardA sample of normally consolidated clay was subjected to a consolidated undrained triaxial compression test that was carried out until the specimen failed at a deviator stress of 50 kN/m2. The pore water pressure at failure was recorded to be 20 kN/m2 and confining pressure of 50 kN/m2 was used in the test. Determine the consolidated undrained friction angle.arrow_forward
- A consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle that the failure plane makes with the major principal axis in degrees. a.54.74 b.24.72 c.16.3 d.19.47arrow_forward2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A consolidated-undrained test was conducted on the clay. Following are the results of the test. Chamber confining pressure = 105 KN/m? Deviator stress at failure = 97 KN/m² a. Compute the pore water pressure developed in the clay specimen at failure. b. Compute the consolidated-undrained friction angle 4. What would have been the deviator stress at failure if a drained test had been conducted with the same chamber confining pressure that is o3= 105 KN/m? C.arrow_forwardQ-3: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: 03 = 276 kN/m² (Aod)f=276 kN/m² Determine a. Angle of friction, o' b. Angle that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress ty on the failure plane d. Determine the effective normal stress on the plane of maximum shear stress Shear stress Š σí σí σ3 Effective stress failure envelope B σ3 = 276 kN/m² A Normal stress 20 σ = 552 kN/m² Ⓒ Cengage Learning 2014arrow_forward
- EFFECTIVE STRESS CONCEPT SITUATION 1: A saturated clay 15 m thick has a void ratio of 0.6 anda specific gravity of 2.7. 5. Which of the following gives the saturated unit weight of clay? a. 18.95 kN/m? C. 20.23 kN/m? b. 19.18 kN/m? d. 24.22 kN/m? 6. Which of the following gives the total vertical stress at the bottom? a. 303.45 kPa C. 355.66 kPa b. 295.66 kPa d. 145.67 kPa 7. Which of the following gives the effective vertical stress at the bottom? a. 197.33 kPa c. 177.21 kPa b. 187.95 kPa d. 156.34 kPaarrow_forward(c) The shear strength of soil collected 4m below ground surface and tested under consolidated undrained test can be given by the equation t = 30 + o' tan 27º by Effective Stress (ES) analysis. A proposed structure of 80 kN/m² is to be constructed on over consolidated clay material with unit weight of 19 kN/m³. Determine: i. Pore water pressure developed in the specimen at failure ii. Minor (63) and major (61) effective principal stress iii. The expected cohesion value in Total Stress (TS) analysisarrow_forward8. For a normally consolidated clay specimen, the results of a drained triaxial test are as follows: Chamber-confining pressure = 125 kN/m? Deviator stress at failure = 175 kN/m? %3D Determine the soil friction angle, o'arrow_forward
- The equation of the effective stress failure envelope for normally consolidated clayey soil is. a drained triaxial test was conducted with the same soil at a chamber confining pressure of 80 KN/m². Deviator at stress failure is (take angle = 250) A 197 KN/m² B 117 KN/m² C 234 KN/m² D 160 KN/m²arrow_forwardA consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle of shearing resistance. a. 16.3 b. 54.74 c. 19.47 d. 24.72arrow_forwardA consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: 03 = 276 kN/m? (Aoa)f = 276 kN/m² Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress tf on the failure plane d. Determine the effective normal stress on the plane of maximum shear stress of Effective stress failure envelope ↑ B of 20 276 kN/m2 A oj = 552 kN/m² Normal stress Shear stress © Cengage Learning 2014arrow_forward
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