The dissociation of molecular iodine into iodine atoms is represented as
I2(g) ⇄ 2I(g)
At 1000 K, the equilibrium constant Kc for the reaction is 3.80 × 10−5. Suppose you start with 0.0456 mole of I2 in a 2.30-L flask at 1000 K. What are the concentrations of the gases at equilibrium?
Interpretation:
The equilibrium concentration
Concept Introduction:
Equilibrium concentration: If Kc and the initial concentration for a reaction and calculate for both equilibrium concentration, and using the (ICE) chart and equilibrium constant and derived changes in respective reactants and products.
Equilibrium constant: Concentration of the products to the respective molar concentration of reactants it is called equilibrium constant. If the K value is less than one the reaction will move to the left side and the K values is higher (or) greater than one the reaction will move to the right side of reaction.
Heterogeneous equilibrium: This equilibrium reaction does not depend on the amounts of pure solid and liquid present, in other words heterogeneous equilibrium, substances are in different phases.
Kp and Kc: This equilibrium constants of gaseous mixtures, these difference between the two constants is that Kc is defined by molar concentrations, whereas Kp is defined by the partial pressures of the gasses inside a closed system.
Vaporized equilibrium: This conversion of liquid in gaseous phase is known as vaporization process. At starting the rate of condensation is less than the rate of evaporation but as evaporation continues the concentration of gaseous molecule in the vapour phase increase.
Answer to Problem 15.60QP
The equilibrium concentration
Explanation of Solution
To find: The each reactant product equilibrium concentration should be identified given the gas phase reaction.
Write and Analyze the given gas phase chemical equilibrium reaction.
The given equilibrium reaction has a homogenous process, then the equilibrium constant can also be represented by Kp, were the Kp represents partial pressure. Then the product molecule partial pressure
To find: Calculate equilibrium concentration (Kp) values for given the statement of equilibrium reaction.
Calculate and analyze the (Kp) values at
We derived here (Kp) values of (I2) dissociation reaction
First we derived the initial concentration of (I2) is
We consider the equilibrium expression in terms of the equilibrium concentration.
The obtained second (x) values are negative concentration, this physically impossible so we omitted this values. First (x) value is correct one.
The given iodine dissociation equilibrium reaction the respective reactant to give the two moles of products in the gas phase and this equilibrium reaction expression contains single conditions like gases phase, the equilibrium constant can also be represented by Kp, were the “P” partial pressure. The each molar concentration values are Kp derived given the gas phase reaction at
The molar concentration (M) values are derived given the iodine
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Chapter 15 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
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