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Concept explainers
a.
Design a low pass filter for a given specification.
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 1P
The obtained value of resistor
Explanation of Solution
Given data:
The value of capacitor
The value of passband gain is
Cutoff frequency is
Formula used:
Refer to Figure 15.1 in the textbook for a first order low-pass filter.
Write the expression for passband gain.
Here,
Write the expression for cutoff frequency.
Calculation:
Write the expression for
Re-arrange equation (2) as follows.
Substitute
Substitute
Convert dB value of passband gain into normal value.
Substitute
Conclusion:
Thus, the obtained value of resistor
b.
Draw the circuit diagram of designed low pass filter.
b.
![Check Mark](/static/check-mark.png)
Explanation of Solution
Calculation:
Modify the Figure 15.1 for designed value as shown in Figure 1.
Conclusion:
Thus, the circuit diagram of designed low pass filter is shown in Figure 1.
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Chapter 15 Solutions
Electric Circuits Plus Mastering Engineering with Pearson eText 2.0 - Access Card Package (11th Edition) (What's New in Engineering)
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