Explanation Given: 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] Concept Used: Basic properties of logarithmic function: ln a + ln b = ln a b ln a − ln b = ln a b n ln a = ln a n Where a > 0 , b > 0 and n is any real number Calculation: To express the quantity in single logarithm 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] Use basic properties of logarithmic functions, as 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] = ln ( x + 2 ) 3 / 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ] , using property n ln a = ln a n = ln ( x + 2 ) + 1 2 [ ln x (

15th Edition

ISBN: 9781305420878

Author: Stewart

Publisher: CENGAGE L

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Question

Chapter 1.5, Problem 41E

To determine

To express the given quantity in single logarithm

13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]

Expert Solution & Answer

Chapter 1 Solutions

BIOCALCULUS:CALCULUS F/LIFE...-W/ACCESS

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

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To express the given quantity in single logarithm 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ]

Solution Summary: The author explains how to express the given quantity in single logarithm.

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To express the given quantity in single logarithm

13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]

Chapter 1 Solutions

To express the given quantity in single logarithm 1 3 ln ( x + 2 ) 3 + 1 2 [ ln x − ln ( x 2 + 3 x + 2 ) 2 ]

Solution Summary: The author explains how to express the given quantity in single logarithm.

Videos

To express the given quantity in single logarithm 13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]

Chapter 1 Solutions

To express the given quantity in single logarithm

13ln(x+2)3+12[lnx−ln( x 2+3x+2)2]