Concept explainers
(a)
Interpretation:
The value of
Concept introduction:
The equilibrium reaction of
Solubility product expression for above reaction will be
Answer to Problem 76QAP
At
Explanation of Solution
The equilibrium reaction of
The solubility product expression for above reaction will be
Above
Hence, at
(b)
Interpretation:
At the above OH concentration
Concept introduction:
If,
If,
If,
Q is ionic product and
Answer to Problem 76QAP
The ions which precipitate at
Explanation of Solution
The concentration of hydroxide ion is as follows:
The precipitation of sodium ions will not take place with OH ion.
The ionic product ( Q) of
From equation (2), ionic product of
As,
From equation (2), ionic product ( Q) of
Or,
From equation (3), ionic product is
Or,
As,
The ionic product ( Q) of
Or,
From equation (4), ionic product is
Or,
As,
(c)
Interpretation:
The percentage of precipitated ions needs to be calculated, if enough
Concept introduction:
The equilibrium reaction of
The expression of solubility productfor above reaction is represented as follows:
The equilibrium reaction of
The expression of solubility productfor above reaction is
The equilibrium reaction of
The expression of solubility productfor above reaction is
Answer to Problem 76QAP
So, under mentioned conditions,
Explanation of Solution
Calculation of
Or,
Also,
Hence, to precipitate
Use above
Hence, final concentration of
Percentage (%) of
Since,
So,
Hence, percentage of
Use
Hence, final concentration of
Percentage (%) of
Since,
So,
Hence, percentage of
So, under mentioned conditions,
(d)
Interpretation:
The mass of precipitateunder the conditions in(c), in one liter of seawater needs to be determined.
Concept introduction:
The total mass of precipitate in one liter precipitate is the sum of mass of precipitate of every ion that is
Answer to Problem 76QAP
Mass of precipitate is
Explanation of Solution
At concentration of
Mass of
Hence, mass of precipitate
Now, mass of
Hence, mass of precipitate
Similarly, mass of
Hence, mass of precipitate
Total mass of precipitate can be calculated as follows:
Hence, mass of precipitate is
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Chapter 15 Solutions
Chemistry: Principles and Reactions
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