# Write a net ionic equation for the reaction between aqueous solutions of (a) ammonia and hydrofluoric acid. (b) perchloric acid and rubidium hydroxide. (c) sodium sulfite and hydriodic acid. (d) nitric acid and calcium hydroxide.

### Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
Publisher: Cengage Learning
ISBN: 9781305079373

### Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
Publisher: Cengage Learning
ISBN: 9781305079373

#### Solutions

Chapter
Section
Chapter 15, Problem 1QAP
Textbook Problem

## Write a net ionic equation for the reaction between aqueous solutions of(a) ammonia and hydrofluoric acid.(b) perchloric acid and rubidium hydroxide.(c) sodium sulfite and hydriodic acid.(d) nitric acid and calcium hydroxide.

Expert Solution

(a)

Interpretation Introduction

Interpretation: The concentration of ammonia for the given conditions of complex ions needs to be determined.

[Cd+2]=[Cd( NH3)4+2]

Concept Introduction: The coordination complexes and complex ions are formed by the combination of metal ion and ligands. Here, ligands are the electron donating atoms or molecules. Therefore, ligands form coordinate bond with metal ion. The stability of coordination complexes can be determined in terms of their formation constant. It is represented as Kf. It is the ratio of product and reactant at equilibrium condition of formation of coordinate complex.

[NH3] =0.014 M

### Explanation of Solution

The formation reaction for [Cd( NH 3)4+2] can be written as:

Cd+2 + 4 NH3 [Cd( NH 3)4+2]

Kf = [Cd( NH 3 )4+2][Cd+2] [NH3]4

Given: [Cd+2]=[Cd( NH3)4+2]

Plug this in Kf expression:

Kf = [Cd ( NH 3 ) 4 +2][Cd ( NH 3 )4 +2 ] [NH3]4[NH3] = [1 Kf]14[NH3] = [1 2 .8 x 10 7 ]14[NH3] =  0.014 M

At [NH3] =0.014 M ; the [Cd+2]=[Cd( NH3)4+2] relation will be true.

Expert Solution

(b)

Interpretation Introduction

Interpretation: The concentration of ammonia for the given conditions of complex ions needs to be determined.

[Co+2]=[Co(NH3)6+2]

Concept Introduction: The coordination complexes and complex ions are formed by the combination of metal ion and ligands. Here ligands are the electron donating atoms or molecules. Therefore, ligands form coordinate bond with metal ion. The stability of coordination complexes can be determined in terms of their formation constant. It is represented as Kf. It is the ratio of product and reactant at equilibrium condition of formation of coordinate complex.

[NH3] =  0.147 M

### Explanation of Solution

The formation reaction for [Co(NH3)6+2] can be written as:

Co+2 + 6 NH3 [Co(NH3)6+2]

Kf = [Co( NH 3 )6+2][Co+2] [NH3]6

Given: [Co+2]=[Co(NH3)6+2]

Plug this in Kfexpression:

Kf = [Co ( NH 3 ) 6 +2] [Co +2 ] [NH3]6[NH3] = [1 Kf]16[NH3] = [1 1 x 10 5 ]16[NH3] =  0.147 M

At [NH3] =0.147 M ; the [Co+2]=[Co(NH3)6+2] relation will be true.

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