Fundamentals of Materials Science and Engineering, Binder Ready Version: An Integrated Approach
Fundamentals of Materials Science and Engineering, Binder Ready Version: An Integrated Approach
5th Edition
ISBN: 9781119175483
Author: William D. Callister Jr., David G. Rethwisch
Publisher: WILEY
Question
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Chapter 15.16, Problem 1QP
To determine

To plot:

The graph of elastic modulus versus the volume percent of tungsten (WC) using upper–and lower–bound expressions.

Expert Solution & Answer
Check Mark

Answer to Problem 1QP

The graph of elastic modulus versus the volume fraction of tungsten (VWC) using upper–and lower–bound modulus of elasticity was plotted and shown Figure 1.

Explanation of Solution

Given:

The modulus of elasticity of cobalt (Co) is, Ec=200GPa(30×106psi) .

The modulus of elasticity of tungsten (WC) is, EWC=700GPa(102×106psi) .

Explanation:

Write the expression for upper–bound modulus of elasticity.

E(u)=ECoVCo+EWCVWC (I)

Write the expression for lower–bound modulus of elasticity.

E(l)=ECoEWCVCoEWC+VWCECo (II)

Here, ECo is the elastic modulus of cobalt, VCo is the volume fraction of cobalt, EWC is the elastic modulus of tungsten and VWC is the volume fraction of tungsten.

Conclusion:

Calculate the upper–bound modulus of elasticity.

When, the volume fraction of cobalt is, VCo=10% and the volume fraction of tungsten is, VCo=90% .

Substitute 200 GPa for ECo , 10% for VCo , 700 GPa for EWC and 90% for VWC in Equation (I).

E(u)=(200GPa)(10100)+(700GPa)(90100)=20+630=650GPa

When, the volume fraction of cobalt is, VCo=90% and the volume fraction of tungsten is, VCo=10% .

Substitute 200 GPa for ECo , 90% for VCo , 700 GPa for EWC and 10% for VWC in Equation (I).

E(u)=(200GPa)(90100)+(700GPa)(10100)=180+70=250GPa

Similarly, the upper–bound modulus of elasticity for different volume fractions are calculated and shown in Table 1.

  VCo   VWC   E(u)
0 100 700
10 90 650
20 80 600
30 70 550
40 60 500
50 50 450
60 40 400
70 30 350
80 20 300
90 10 250
100 0 200

Table 1

Calculate the lower–bound modulus of elasticity.

When, the volume fraction of cobalt is, VCo=10% and the volume fraction of tungsten is, VCo=90% .

Substitute 200 GPa for ECo , 10% for VCo , 700 GPa for EWC and 90% for VWC in Equation (II).

E(l)=(200GPa)(700GPa)(10100)(700GPa)+(90100)(200GPa)=14000070+180=560GPa

When, the volume fraction of cobalt is, VCo=90% and the volume fraction of tungsten is, VCo=10% .

Substitute 200 GPa for ECo , 90% for VCo , 700 GPa for EWC and 10% for VWC in Equation (I).

E(l)=(200GPa)(700GPa)(90100)(700GPa)+(10100)(200GPa)=140000630+20=215.3846GPa

Similarly, the lower–bound modulus of elasticity for different volume fractions are calculated and shown in Table 2.

  VCo   VWC   E(l)
0 100 700
10 90 560
20 80 466.67
30 70 400
40 60 350
50 50 311.11
60 40 280
70 30 254.55
80 20 233.33
90 10 215.38
100 0 200

Table 2

Refer Table 1 and Table 2.

Take the volume fraction of tungsten (VWC) in x–axis and take upper–bound modulus of elasticity [E(u)] , lower–bound modulus of elasticity [E(l)] in y–axis.

Plot the graph of elastic modulus versus the volume fraction of tungsten (VWC) using upper–and lower–bound modulus of elasticity as shown Figure 1.

Fundamentals of Materials Science and Engineering, Binder Ready Version: An Integrated Approach, Chapter 15.16, Problem 1QP

Thus, the graph of elastic modulus versus the volume fraction of tungsten (VWC) using upper–and lower–bound modulus of elasticity was plotted and shown Figure 1.

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