PHYSICS F/SCIEN.+ENGRS. W/SAPLING >IC<
6th Edition
ISBN: 9781319336127
Author: Tipler
Publisher: MAC HIGHER
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Chapter 16, Problem 13P
To determine
The way, to estimate the temperature of the air in the organ pipe using its resonance frequencies.
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The resonance frequency f of a closed air column is known to depend on the pressure density p of air and the length of air column l. How re these quantities related
Hot chocolate effect. Tap a metal spoon inside amug of water and note the frequency fi you hear. Then add aspoonful of powder (say, chocolate mix or instant coffee) and tapagain as you stir the powder. The frequency you hear has a lowervalue fs because the tiny air bubbles released by the powderchange the water’s bulk modulus. As the bubbles reach the watersurface and disappear, the frequency gradually shifts back to itsinitial value. During the effect, the bubbles don’t appreciablychange the water’s density or volume or the sound’s wavelength. Rather, they change the value of dV/dp—that is, the differentialchange in volume due to the differential change in the pressurecaused by the sound wave in the water. If fs /fi=0.333, what is theratio (dV/dp)s/(dV/dp)i?
An organ pipe is used to produce the lowest note audible to the human ear - 20.-Hz. If the temperature is 25 °C, then how long is the organ pipe? (First decide whether it will produce this low note as a closed- or as an open-end air column.)
Chapter 16 Solutions
PHYSICS F/SCIEN.+ENGRS. W/SAPLING >IC<
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Ch. 16 - Prob. 11PCh. 16 - Prob. 12PCh. 16 - Prob. 13PCh. 16 - Prob. 14PCh. 16 - Prob. 15PCh. 16 - Prob. 16PCh. 16 - Prob. 17PCh. 16 - Prob. 18PCh. 16 - Prob. 19PCh. 16 - Prob. 20PCh. 16 - Prob. 21PCh. 16 - Prob. 22PCh. 16 - Prob. 23PCh. 16 - Prob. 24PCh. 16 - Prob. 25PCh. 16 - Prob. 26PCh. 16 - Prob. 27PCh. 16 - Prob. 28PCh. 16 - Prob. 29PCh. 16 - Prob. 30PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Prob. 33PCh. 16 - Prob. 34PCh. 16 - Prob. 35PCh. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - Prob. 43PCh. 16 - Prob. 44PCh. 16 - Prob. 45PCh. 16 - Prob. 46PCh. 16 - Prob. 47PCh. 16 - Prob. 48PCh. 16 - Prob. 49PCh. 16 - Prob. 50PCh. 16 - Prob. 51PCh. 16 - Prob. 52PCh. 16 - Prob. 53PCh. 16 - Prob. 54PCh. 16 - Prob. 55PCh. 16 - Prob. 56PCh. 16 - Prob. 57PCh. 16 - Prob. 58PCh. 16 - Prob. 59PCh. 16 - Prob. 60PCh. 16 - Prob. 61PCh. 16 - Prob. 62PCh. 16 - Prob. 63PCh. 16 - Prob. 64PCh. 16 - Prob. 65PCh. 16 - Prob. 66PCh. 16 - Prob. 67PCh. 16 - Prob. 68PCh. 16 - Prob. 69PCh. 16 - Prob. 70PCh. 16 - Prob. 71PCh. 16 - Prob. 72PCh. 16 - Prob. 73PCh. 16 - Prob. 74PCh. 16 - Prob. 75PCh. 16 - Prob. 76PCh. 16 - Prob. 77PCh. 16 - Prob. 78PCh. 16 - Prob. 79PCh. 16 - Prob. 80PCh. 16 - Prob. 81PCh. 16 - Prob. 82PCh. 16 - Prob. 83PCh. 16 - Prob. 84PCh. 16 - Prob. 85PCh. 16 - Prob. 86P
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- A string has a length of 1.5 m, a linear mass density =0.008 kg/m, , and a tension of 120 N. If the air temperature is T=22C , what should the length of a pipe open at both ends for it to have the same frequency for the n=3 mode?arrow_forwardA truck manufacturer finds that a strut in the engine is failing prematurely. A sound engineer determines that the strut resonates at the frequency of the engine and suspects that this could be the problem. What are two possible characteristics of the strut can be modified to correct the problem?arrow_forwardA string has a linear mass density µ, a length L, and a tension of FT, and oscillates in a mode n at a frequency f. Find the ratio of ff for a small change in tension.arrow_forward
- Two strings are attached to poles, however the first string is twice the linear mass density mu of the second. If both strings have the same tension, what is the ratio of the speed of the pulse of the wave from the first string to the second string?arrow_forwardA crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one end. (a) What is the fundamental frequency if the tube is 0.240 m long, by taking air temperature to be 37.0°C ? (b) What would this frequency become if the person replaced the air with helium? Assume the same temperature dependence for helium as for air.arrow_forwardA bat sends of a sound wave 100 kHz and the sound waves travel through air at a speed of v=343 m/s. (a) If the maximum pressure difference is 1.30 Pa, what is a wave function that would model the sound wave, assuming the wave is sinusoidal? (Assume the phase shift is zero.) (b) What are the period and wavelength of the sound wave?arrow_forward
- A nylon guitar string is fixed between two lab posts 2.00 m apart. The string has a linear mass density of =7.20 g/m and is placed under a tension of 160.00 N. The string is placed next to a tube, open at both ends, of length L. The string is plucked and the tube resonates at the n=3 mode. The speed of sound is 343 m/s. What is the length of the tube?arrow_forwardCheck Your Understanding A famous magic trick involves a performer singing a note toward a crystal glass until the glass shatters. Explain why the trick works in terms of resonance and natural frequency.arrow_forwardA barrel organ is shown in Figure P18.38. Such organs are much smaller than traditional organs, allowing them to fit in smaller spaces and even allowing them to be portable. Use the photo to estimate the range in fundamental frequencies produced by the organ pipes in such an instrument. Assume the pipes are open at both ends. How does that range compare to a piano whose strings range in fundamental frequency from 21.7 Hz to 4186.0 Hz? FIGURE P18.38arrow_forward
- A sound wave of a frequency of 2.00 kHz is produced by a string oscillating in the n=6 mode. The linear mass density of the string is =0.0065 kg/m and the length of the string is 1.50 m. What is the tension in the string?arrow_forwardYou are given two wind instruments of identical length. One is open at both ends, whereas the other is closed at one end. Which is able to produce the lowest frequency?arrow_forwardWine glasses can be set into resonance by moistening your finger and rubbing it around the rim of the glass. Why?arrow_forward
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